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To apply this theorem, evaluate the function r(0) = sec 0 - π 8 (Round to the nearest hundredth as needed.) +5 at each endpoint of the interval

To apply this theorem, evaluate the function r(0) = sec 0 - π 8 (Round to the nearest hundredth as needed.) +5 at each endpoint of the interval

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
To apply this theorem, evaluate the function \( r(\theta) = \sec \theta - \frac{1}{\theta^3} + 5 \) at each endpoint of the interval \(\left[ \frac{\pi}{8}, \frac{\pi}{4} \right]\). \[ r\left( \frac{\pi}{8} \right) = \ \_\_\_\_ \quad (\text{Round to the nearest hundredth as needed.}) \]
Transcribed Image Text:To apply this theorem, evaluate the function \( r(\theta) = \sec \theta - \frac{1}{\theta^3} + 5 \) at each endpoint of the interval \(\left[ \frac{\pi}{8}, \frac{\pi}{4} \right]\). \[ r\left( \frac{\pi}{8} \right) = \ \_\_\_\_ \quad (\text{Round to the nearest hundredth as needed.}) \]
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