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To a sample of a protein hydroysate, an analyst added 1.00 mg of tryptophan, which was labeled with 14C and exhibited a counting rate of 584 cpm above background. The labeled compound was thoroughly mixed with the sample and the mixture was passed through an ion-exchange column. The fraction effluent contaning only tryptophan was collected, and from it an 18.0 mg sample of pure tryptophan was isolated. The isolated sample had a counting rate of 204 cpm in the same counter. What was the weight of tryptophan in the original sample? A. 6.28 mg B. 20.8 mg C. 50.5 mg D. 58.4 mg Help me! Why is C correct. Please explain! Thank you.

To a sample of a protein hydroysate, an analyst added 1.00 mg of tryptophan, which was labeled with 14C and exhibited a counting rate of 584 cpm above background. The labeled compound was thoroughly mixed with the sample and the mixture was passed through an ion-exchange column. The fraction effluent contaning only tryptophan was collected, and from it an 18.0 mg sample of pure tryptophan was isolated. The isolated sample had a counting rate of 204 cpm in the same counter. What was the weight of tryptophan in the original sample? A. 6.28 mg B. 20.8 mg C. 50.5 mg D. 58.4 mg Help me! Why is C correct. Please explain! Thank you.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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To a sample of a protein hydroysate, an analyst added 1.00 mg of tryptophan, which was labeled with 14C and exhibited a counting rate of 584 cpm above background. The labeled compound was thoroughly mixed with the sample and the mixture was passed through an ion-exchange column. The fraction effluent contaning only tryptophan was collected, and from it an 18.0 mg sample of pure tryptophan was isolated. The isolated sample had a counting rate of 204 cpm in the same counter. What was the weight of tryptophan in the original sample? A. 6.28 mg B. 20.8 mg C. 50.5 mg D. 58.4 mg Help me! Why is C correct. Please explain! Thank you.
Transcribed Image Text:To a sample of a protein hydroysate, an analyst added 1.00 mg of tryptophan, which was labeled with 14C and exhibited a counting rate of 584 cpm above background. The labeled compound was thoroughly mixed with the sample and the mixture was passed through an ion-exchange column. The fraction effluent contaning only tryptophan was collected, and from it an 18.0 mg sample of pure tryptophan was isolated. The isolated sample had a counting rate of 204 cpm in the same counter. What was the weight of tryptophan in the original sample? A. 6.28 mg B. 20.8 mg C. 50.5 mg D. 58.4 mg Help me! Why is C correct. Please explain! Thank you.
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