- t(n + 1) = 5t(n) 4t(n - 1) ;n≥2 t(0) = 1 t(1) = 2

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Solve the following homogeneous recurrence equation and obtain the general solution and the solution based on the initial condition

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t(n + 1) = 5t(n) 4t(n - 1) ;n≥2
t(0) = 1
t(1) = 2
Transcribed Image Text:- t(n + 1) = 5t(n) 4t(n - 1) ;n≥2 t(0) = 1 t(1) = 2
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