TLB LRU MEM LRU 5 A 5 A B 3 2 3 4 5 6 7 8 OSA B D E F 9 C 0 2 3 1 1 1 1 1 1. Show the breakdown of the virtual address. 2. Show the breakdown of the physical address. 3. Show the breakdown of the physical address as interpreted by the cache system. 4. Calculate the physical address for the Ox92220 virtual address. 5. Calculate the tag, set, and offset used to locate the above address (in d) in the cache. 6. Illustrate the different actions involved in accessing the above address (in d). Indicate the changes applied to the TLB, page table, and the two LRU stacks.

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Consider a system with 256K bytes of physical memory, the size of each page is 64K
bytes, and the virtual address space is 1M. The system is byte-addressable. The
processor has a 2 entry TLB and a 16Kbyte 2-way set associative cache with 512 bytes
per block. An LRU replacement strategy is implemented on both of the TLB and physical
memory levels. The following tables describe the current state of the memory system.
TLB
0
1
Virtual page
0x5
OXA
Frame
(physical)
TLB LRU
MEM LRU
2
3
5
A
5
A
B
3
Page Table
0
1
2
3
4
5
6
7
8
SAB CD EF
9
А
с
Frame
(physical)
0
2
3
1
Validity bit
1
1
1
1
1. Show the breakdown of the virtual address.
2. Show the breakdown of the physical address.
3. Show the breakdown of the physical address as interpreted by the cache system.
4. Calculate the physical address for the Ox92220 virtual address.
5. Calculate the tag, set, and offset used to locate the above address (in d) in the cache.
6. Illustrate the different actions involved in accessing the above address (in d). Indicate
the changes applied to the TLB, page table, and the two LRU stacks.
Transcribed Image Text:Consider a system with 256K bytes of physical memory, the size of each page is 64K bytes, and the virtual address space is 1M. The system is byte-addressable. The processor has a 2 entry TLB and a 16Kbyte 2-way set associative cache with 512 bytes per block. An LRU replacement strategy is implemented on both of the TLB and physical memory levels. The following tables describe the current state of the memory system. TLB 0 1 Virtual page 0x5 OXA Frame (physical) TLB LRU MEM LRU 2 3 5 A 5 A B 3 Page Table 0 1 2 3 4 5 6 7 8 SAB CD EF 9 А с Frame (physical) 0 2 3 1 Validity bit 1 1 1 1 1. Show the breakdown of the virtual address. 2. Show the breakdown of the physical address. 3. Show the breakdown of the physical address as interpreted by the cache system. 4. Calculate the physical address for the Ox92220 virtual address. 5. Calculate the tag, set, and offset used to locate the above address (in d) in the cache. 6. Illustrate the different actions involved in accessing the above address (in d). Indicate the changes applied to the TLB, page table, and the two LRU stacks.
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