Question 2 tions are mixed. As noted earlier, you could do these calculations befocoming to the laboratory.2. Calculate the equilibrium [FESCN2"] in each tube from the followingequation:[FESCN2 1(test tube x) = [PESCN2+I(test tube A) xAbsorbance(test tube x)Absorbance(test tube A)test tobe x = 0.080.test tube A =Absocbance X =Absorbance A = 0,57%3D0.200O,48

Given the concentration of test tube X = 0.080 M Concentration of test tube A = 0.200 M Absorbance…

tions are mixed. As noted earlier, you could do these calculations befo coming to the laboratory. 2. Calculate the equilibrium [FESCN21 in each tube from the following equation: [FESCN2 ](test tube x) = [FESCN21(test tube A) x Absorbance(test tube x) Absorbance(test tube A) %3D test tobe x = O.080 test tube A = 0.200 Absocbance x = Absorbance A = 0,57 %3D %3D O,48

tions are mixed. As noted earlier, you could do these calculations befo coming to the laboratory. 2. Calculate the equilibrium [FESCN21 in each tube from the following equation: [FESCN2 ](test tube x) = [FESCN21(test tube A) x Absorbance(test tube x) Absorbance(test tube A) %3D test tobe x = O.080 test tube A = 0.200 Absocbance x = Absorbance A = 0,57 %3D %3D O,48

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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