The mature eucalyptus trees in a forest vary. It is known that the population of heights of all mature eucalyptuses in the forest is approximatelynormally distributed. An article in a conservation journal claims that the standard deviation of this population is 8.14 m. You are a researcher who wants to testthis claim with a random sample of 41 mature eucalyptuses from the forest.Based on your sample, follow the steps below to construct a 95% confidence interval for the population standard deviation of all mature eucalyptus heights inthe forest. Then state whether the confidence interval you construct contradicts the article's claim. (If necessary, consult a list of formulas.)(a) Click on "Take Sample" to see the results from the random sample.Take SamplePoint estimate of thepopulation variance:0Number of matureeucalyptuses41Sample size:ПSample mean88.2695% confidence interval for thepopulation variance:XSample standardTo find the confidence interval for the population standard deviation, first find the confidence interval for the population variance.Enter the values of the point estimate of the population variance, the sample size, the left critical value, and the right critical value you need for your95% confidence interval for the population variance. (Choose the correct critical values from the table of critical values provided.) When you aredone, select "Compute".Śdeviation5.48Sample variance30.0304 (b)Sample size:0Left critical value:7Right critical value:1Compute0.000.00population variance:95% confidence interval for thepopulation standard deviation:2.004.005.00RightX0.995=20.707 %0.005=66.7666.00Critical valuesLeft=2X0.975 24.433 0.025 59.342Based on your sample, graph the 95% confidence interval for the population standard deviation of all mature eucalyptus heights in the forest.• Enter the values for the lower and upper limits on the graph to show your confidence interval. Round the values to two decimal places.For the point (◆) enter the claim 8.14 from the article on your graph.2=95% confidence interval for the population standard deviation:22X0.950 26.509 X0.050=55.758= =8.0010.0010.00

Answered: Image /qna-images/answer/38922ec4-9207-4e78-9cf1-0328a0ee2281.jpg

Answered: tion journal claims that the standard…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The newest model of a car battery from a popular brand is supposed to have a lifetime of 60 months, but the lifetime varies slightly from battery to battery. It is known that the population of all lifetimes (in months) of this model of car battery is approximately normally distributed. You are a product reviewer who wants to estimate the standard deviation for this population with a random sample of 22 car batteries. Follow the steps below to construct a 99% confidence interval for the population standard deviation of all lifetimes of this model of car battery. (If necessary, consult a list of formulas.) (a)Click on "Take Sample" to see the results from the random sample. Take Sample Number of carbatteries Sample mean Sample standard deviation Sample variance To find the confidence interval for the population standard deviation, first find the confidence interval for the population variance. Enter the values…
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