tinuous lateral support. Blank 1 unbraced length of 10 ft with Cb = 1.0. Blank 2 unbraced length of 20 ft with Cb = 1.0. Blank 3 W12x35 A= 10.30 n2 12.500 in. tw 0.300 in. bf 6.580 in. 0.520
tinuous lateral support. Blank 1 unbraced length of 10 ft with Cb = 1.0. Blank 2 unbraced length of 20 ft with Cb = 1.0. Blank 3 W12x35 A= 10.30 n2 12.500 in. tw 0.300 in. bf 6.580 in. 0.520
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![Determine the design flexural strength in ft kips of a W12 x 35 of A242 (Fy = 50ksi) steel subject to
a. Continuous lateral support. Blank 1
b. An unbraced length of 10 ft with Cb = 1.0. Blank 2
C. An unbraced length of 20 ft with Cb = 1.0. Blank 3
W12x35
...
10.30
in2
d=
12.500
in.
tw =
0.300
in.
bf =
6.580
in.
0.520
in.
T=
10-1/9
in.
k=
0.8200
in.
k1 =
0.7500
In.
gage
3 1/2
In.
it
d'Af =
1.740
n.
3.88
205.00
n.4
Sx-
45.80
n.3
IX=
5.250
n.
ly=
Sy =
24.50
7.47
In.43
ry =
1.540
n.
Zx =
Zy =
J=
Cw =
51.20
n.3
n.3
11.50
0.74
in.4
879
n.6
a =
55.42
n.
Wno =
19.60
m2
Sw=
18.80
n.4
9.75
in43
Qw =|
25.40
in.3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1b6962e2-d49f-4256-8140-298dd61db166%2Ffc15022b-8be6-496d-b0ae-423a387eb2c5%2Fjqitw0k_processed.png&w=3840&q=75)
Transcribed Image Text:Determine the design flexural strength in ft kips of a W12 x 35 of A242 (Fy = 50ksi) steel subject to
a. Continuous lateral support. Blank 1
b. An unbraced length of 10 ft with Cb = 1.0. Blank 2
C. An unbraced length of 20 ft with Cb = 1.0. Blank 3
W12x35
...
10.30
in2
d=
12.500
in.
tw =
0.300
in.
bf =
6.580
in.
0.520
in.
T=
10-1/9
in.
k=
0.8200
in.
k1 =
0.7500
In.
gage
3 1/2
In.
it
d'Af =
1.740
n.
3.88
205.00
n.4
Sx-
45.80
n.3
IX=
5.250
n.
ly=
Sy =
24.50
7.47
In.43
ry =
1.540
n.
Zx =
Zy =
J=
Cw =
51.20
n.3
n.3
11.50
0.74
in.4
879
n.6
a =
55.42
n.
Wno =
19.60
m2
Sw=
18.80
n.4
9.75
in43
Qw =|
25.40
in.3
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