TInterval Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. E Click the icon to view a t distribution table (13.046,22.15) x= 17.598 Sx= 16.01712719 n= 50 a. What is the number of degrees of freedom that should be used for finding the critical value t2? df = 49 (Type a whole number) b. Find the critical value t,12 corresponding to a 95% confidence level. ta/2 0 (Round to two decimal places as needed.)

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Question
1
---

Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below.

![Icon for viewing t distribution table]

TInterval
(13.046, 22.15)
x̄ = 17.598
Sx = 16.01712719
n = 50

a. What is the number of degrees of freedom that should be used for finding the critical value *t*α/2?

df = 49  
(Type a whole number.)

b. Find the critical value *t*α/2 corresponding to a 95% confidence level.

*t*α/2 = ☐  
(Round to two decimal places as needed.)

---

Diagram Explanation:

The diagram illustrates a t-distribution interval and contains the following information:
- The confidence interval is given as (13.046, 22.15).
- The sample mean (x̄) is 17.598.
- The sample standard deviation (Sx) is 16.01712719.
- The sample size (n) is 50.

A degree of freedom is calculated as n - 1, which in this case is 49. The critical value for t (t*α/2) is to be found using a 95% confidence level and rounded to two decimal places.
Transcribed Image Text:--- Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. ![Icon for viewing t distribution table] TInterval (13.046, 22.15) x̄ = 17.598 Sx = 16.01712719 n = 50 a. What is the number of degrees of freedom that should be used for finding the critical value *t*α/2? df = 49 (Type a whole number.) b. Find the critical value *t*α/2 corresponding to a 95% confidence level. *t*α/2 = ☐ (Round to two decimal places as needed.) --- Diagram Explanation: The diagram illustrates a t-distribution interval and contains the following information: - The confidence interval is given as (13.046, 22.15). - The sample mean (x̄) is 17.598. - The sample standard deviation (Sx) is 16.01712719. - The sample size (n) is 50. A degree of freedom is calculated as n - 1, which in this case is 49. The critical value for t (t*α/2) is to be found using a 95% confidence level and rounded to two decimal places.
Expert Solution
Step 1

GivenMean(x)=17.598standard deviation(s)=16.011712719sample size(n)=50Confidence Interval = 95%

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