ss Statistics 1 || Spring21Time left 1:57:5cIn a survey of 472 personnel directors, 63% thought that they would be hiring new personnel over the next three months. Which ofthe following represents a 98% confidence interval for the proportion of all personnel directors planning to hire personnel over thenext three months?0.63 + 0.057O b. 0.63 ±0.047O . 0.63 +0.042O d. 0.63 ± 0.052NEXT PAGEOUS PAGEMAYétv23MacBook Air888F9F7F4F5F2F3&!@#$%234561QWERYASFGLs* 00

Introduction : Confidence interval : In the method of point estimation we estimate the estimator…

Answered: Time left 1:57:5 In a survey of 472…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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QUESTION 22 A car insurance company wanted information about the age of its customers. A researcher computed 90%, 95%, 97%, and 99% confidence intervals for the population mean age of the customers. Which of the following intervals is the the 97% confidence interval for the population mean age? (36.30, 39.70) O (36.70, 39.30) (36.56, 39.44) (36.91, 39.09)
If we find a 95% confidence interval using a sample, then we can say... 95% of individuals will fall on that interval there is a 5% chance the population proportion is NOT on the interval. 95% of our samples will fall on that interval. No answer text provided.
You are interested in constructing a 95% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 405 randomly selected caterpillars observed, 54 lived to become butterflies. Round answers to 4 decimal places where possible. a. With 95% confidence the proportion of all caterpillars that lived to become a butterfly is between and . b. If many groups of 405 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion.
You are interested in constructing a 90% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 378 randomly selected caterpillars observed, 45 lived to become butterflies. Round answers to 4 decimal places where possible. a. With 90% confidence the proportion of all caterpillars that lived to become a butterfly is between and . b. If many groups of 378 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion.
Mental health. The General Social Survey asked the question: “For how many days during the past30 days was your mental health, which includes stress, depression, and problems with emotions, not good?”Based on responses from 1,151 US residents, the survey reported a 95% confidence interval of 3.40 to 4.24days in 2010.(a) Interpret this interval in context of the data.(b) What does “95% confident” mean? Explain in the context of the application.(c) Suppose the researchers think a 99% confidence level would be more appropriate for this interval. Willthis new interval be smaller or wider than the 95% confidence interval?(d) If a new survey were to be done with 500 Americans, do you think the standard error of the estimatebe larger, smaller, or about the same.
Let (a,b) be 90% confidence interval for 0 , then p(a < 0
Through polling, it was estimated that the percent of people who will vote for a particular candidate in an upcoming election is 36.2%. If the margin of error is 3.5, give the confidence interval for the percentage of people who will vote for the candidate in the upcoming election.% to %
2. According to the website Rotten Tomatoes, 94% of people who watched the Netflix show Stranger Things liked it. Since UR students tend to be scientifically minded, we hypothesize that less than 94% of UR students like the show. Out of 219 surveyed UR students, 198 indicated they like Stranger Things. Use the built in prop.test() function to: a. Construct a 90% confidence interval for the proportion of UR students who like Stranger Things. b. Test at the a=0.10 significance level whether the proportion of students who like Stranger Things is LESS THAN 0.94. What conclusion do you reach?
If you want to be confident in your estimation of a confidence interval, you should use….
The ?z value for a 96.6% confidence interval estimate is A. 1.96 B. 2.00 C. 2.12 D. 1.82
In a sample of 100 college students, 25 of them own a car. Calculate the 95% confidence interval for the true population of college students who own a car. Choose the closest one. A. (0.165132, 0.334868) B. (0.231725, 0.452302) C. (0.25, 0.75) D. (0.1, 0.9)
A random sample of 1000 NAU students in Flagstaff found 470 NAU students who drink coffee daily. Find a 95% confidence interval for the true percent of NAU students in Flagstaff who drink coffee daily. Express your results to the nearest hundredth of a percent. Answer ___to____%

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