Time left 0:. Suppose the random variable X follows a normal distribution with mean 70 and variance 100. Then the probability is 0.6826 that X is in the symmetric interval about the mean between two numbers are O A 60 and 80 O B. -1 and 1 OC. 70 and 90 O D. None

Time left 0:. Suppose the random variable X follows a normal distribution with mean 70 and variance 100. Then the probability is 0.6826 that X is in the symmetric interval about the mean between two numbers are O A 60 and 80 O B. -1 and 1 OC. 70 and 90 O D. None

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Related questions

Q: Assume that X is a normally distributed random variable and Z is the corresponding standard normal…

Q: Q3: Let i be the observed mean of a random sample of size n from a distribution having mean u and…

A: Hello! As you have posted 2 different questions, we are answering the first question. In case you…

Q: 5. X is a normally distributed random variąble with a meah of 8 and a standard deviation of 3. The…

A: From the provided information, Mean (µ) = 8 Standard deviation (σ) = 3 X~N (8, 3)

Q: Assume the random variable X is normally distributed, with mean u=57 and standard deviation o = 7.…

A: The random variable X is normally distributed The population mean is 57. The population standard…

Q: Do the following. Find the mean of the probability distribution of the which can take only the…

Q: and let Consider a random variable X with the following distribution r 13 4 7 8 P(X=x) 0.2 0.25 0.1…

A: (a) To calculate the mean of X, we multiply each value of X by its corresponding probability and sum…

Q: 2n- 50 and p= 0.45

A: Given, Let, n =number of trials p =the probability of success q=1-p

Q: Suppose the random variableXfollows a normal distribution with mean 80 and variance 100. Then the…

A: μ = 80 , σ = 100= 10

Q: 3. Z is a standard normal random variable. What is the value of Z if the area to the right of Z is…

Q: Q4 The weight of McMaster students is Gaussian distributed with mean 86kg and standard deviation…

A: Given that: Mean = 86 kg S. D = 8 kg By using standard normal distribution z score...

Q: Find the variance of a binomial distribution when p = 73% and n = 205. (

A: Note :- Variance=np(1-p) in our question Given that p=73%=.73 And n=205 So

Q: Assume that adults have IQ scores that are normally distributed with a mean of 105 and a standard…

Q: Random variable X is normally distributed with mean 18 and variance 9. If P(k<X<21) = 0.2045, find…

Q: Let random variable X have a normal distribution with =810 and a=95. Find the number a such that…

A: given data normal distributionμ = 810σ = 95P(810-a<x<810+a) = 0.762a = ?

Q: use calculator me: Band: Due Date: Let x be a random variable that represents the weights in…

A: Step 1: Step 2: Step 3: Step 4:

Q: Suppose the random variable X follows a normal distribution with mean 80 and variance 100. Then the…

A: X~Nμ=80, σ2=100 Standard deviation σ=100=10

Q: 1. Let X be a random variable with probability f(z) = { I= 1,2, 3, 10, elsewhere. Find the…

A: As per our company guidelines we are supposed to answer only first question. Kindly repost other…

Q: Ch: Estimating Random Variables Q: The minimum of two independent exponential random variables with…

A: In this problem, we are given that we have two independent exponential random variables with a mean…

Q: 1. X is a normally distributed random variable with mean 50 and standard deviation 5. What is the…

Q: Suppose the random variable Z follows a standard normal distribution. Then the probability is 0.67…

A: Given that,The random variable Z follows a standard normal distribution.

Q: Suppose we are given a sample of 60 observations from a distribution whose mean is O and variance is…

A: The mean is 0 and the variance is 3/5.

Q: Suppose the number of rides that a visitor enjoys at Disney World during a day is a random variable…

A: Formulae : Mean : μ = ∑xp(x) Standard deviation : σ = ∑(x-μ)2P(x)

Q: The data in tabulated form shown below are the number of children of family in each worker in a…

A: Given information: Worker Number of boys Number of girls Number of children A 3 1 4 B 4 2 6…

Q: Suppose that the grades of Mathematics module is modeled well by a normal probability distribution…

A: Given: μ=220 and σ=130. It is also given that a=-b.…

Q: 4 6. 8. P(X) 1 k 3. What should be the value of k to complete the probability distribution? A. 0 D.…

A: 3. The value of k is obtained as follows: ∑xPX=116+16+k+16+16=146+k=1k=1-46=6-46=26=13 Thus, the…

Q: For the discrete probability distribution. 1 3 4 5 7 f k 2k 2k 3k k² 2k² 7k² + k Find the variance.

Q: In testing of electric cables, the probability that any particular cable will be defective is .04.…

A: Given that, In testing of electric cables, the probability that any particular cable will be…

Q: Suppose the random variableX follows a normal distribution with mean 80 and variance 100. Then the…

A: Given Mean μ=80 Variance =100 Standard Deviation σ=variance =100=10 Probability =0.6826

Q: Let x2-z,2+ z22. Za is chi-square distribution random variable, where df = 54. What is the standard…

Q: 2. The time Xit takes Professor Sawyer to drive to campus on a randomly selected day follows a…

A: Introduction: The random variable X denotes the time taken by the professor to drive to campus on a…

Q: A fair coin was tossed 2 times. x is the number of tails occurred. Assuming x be a discrete random…

A: Given information : given that a fair coin was tossed 2 times. let x is the number of tails…

Q: Suppose the random variableXfollows a normal distribution with mean 70 and variance 100. Then the…

Q: An elevator has a placard stating that the maximum capacity is 3800 lb-26 passengers. So, 26 adult…

A: From given data we have : mean μ=189 Standard deviation σ=36

Q: Suppose the random variable X follows a normal distribution with mean 70 and variance 100. Then the…

A: Correct answer is (C) -1 and 1

Q: Suppose the random variableX follows a normal distribution with mean 80 and variance 100. Then the…

A: Given Data: Mean=80 Variance=100 X~ Normal (80, 100)

Q: A random variable X is normally distributed, with µ = 10,0 = 2 . (a) Calculate the z-score for X =…

A: Given Information: X is normally distributed with mean μ=10 and standard deviation σ=2 (a) To…

Q: b) P(-1.102.13) 27

A: Question 10)The Z is the standard normal variable.

Q: The random variable X has a binomial distribution with n=20 and p 0.01. What is the mean and…

A: As in binomial distribution Mean = n*p variance = n*p*(1-p)

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

20) (page 16 of 35) - Google Chrome
d/quiz/attempt.php?attempt=D1894453&cmid38898478&page=15
STEM (ACADEMIC)
- Statistics 1 (section20) || spring21
Time left 0:26:06
Suppose the random variable X follows a normal distribution with mean 70 and variance 100, Then the probability is 0.6826 that X is in the
symmetric interval about the mean between two numbers are
O A. 60 and 80
O B. -1 and 1
O C. 70 and 90
O D. None
AGE
NEXT PAGE
mere to search
acer
F5
PrtSc
SysRq
F6
F7
F8
F10
F11
F12
Pause
DIO
国。
Sar Lk
Break
%23
*
4
5
7
V
8 A
9.
%3D
3.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.

Similar questions

K- The average number of acres burned by forest and range fres in a large county is 3,800 acres per year, with a standard deviation of 550 acres. The distribution of the number of acres burned is normal a Compute the probability that more than 4,000 acres will be burned in any year b. Determine the probability that fower than 3,000 acres will be burned in any year What is the probability that between 2,500 and 3,400 acres will be burned? d in those years when more than 4,500 acres are burned, help is needed from eastern region fire teams Determine the probability help will be needed in any year CRED
8. Let X be a uniform random variable and P(X7)=0.15. Calculate the mean value and the variance. Find the probability P(X>6).
Let X be a normally distributed random variable with a mean of 12 and a standard deviation of 1.25. What proportion of the values of X are less than 14? 0.945 0.933 0.625 None of these choices
Mean and Standard Deviation. Assume that the random variable X is normally distributed, with mean =70 and standard deviation =16. Which of the following is the probability that X is less than 90?
Q2
Help
Suppose Y is normally distributed with mean = -3 and variance equal to 4. Find the probability that Y is less than or equal to -0.3. Hint, you must standardize the random variable. 0.9115 0.4602 0.5832 0.1
Q6
refer to the photo
I. TRUE OR FALSE. Choose A if the statement is always true, otherwise choose B. 1. The sum of the probabilities of all values of the random variable must be equal to 1. 2. The capacity of water dams in a region is an example of continuous random variable. 3. The formula u = is used to compute for the mean of a probability distribution. IxF(x) 4. A standard normal curve is a normal probability distribution that has a mean of one and standard deviation of one 5. The width of the curve in normal distribution is determined by the mean of the distribution. 6. The mean of the sampling distribution of the sample means is less than the population mean. 7. The standard error of the mean is the standard deviation of the sampling distribution of the sample means. 8. The sampling variability of the sample means becomes smaller as the sample size n gets larger. 9. In estimating the mean, the degrees of freedom is equal to (n - 1) when using the t- distribution. 10. The t-distribution is asymmetric…
p1. Need help
3. We are throwing a die twice. Find the distribution of the random variable |X – Y|= (difference of scored points). Find its mean value and variation. [Ans. E(|X – Y|) = 1,94 ]