Can you explain what is happening in the diagrams Timeค)I/O operation;processor waitsI/O operation;processor waits2a2b3bI/O operationconcurrent withprocessor executing(b) With interrupts(a) Without interruptsFigure 3.10 Program Timing: Short I/O WaitTimeI/O operation;processor waitsI/O operationconcurrent withprocessor executingI/O operation;processor waitsΘΘ Θ3I/O operationconcurrent withprocessor executing;then processorwaitsI/O operationconcurrent withprocessor executing;then processorwaits(b) With interrupts(a) Without interruptsFigure 3.11 Program Timing: Long I/O Wait

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Answered: Time ค) I/O operation; processor waits…

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter4: Processor Technology And Architecture

Section: Chapter Questions

Problem 3PE: Processor R is a 64-bit RISC processor with a 2 GHz clock rate. The average instruction requires one...

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How many times the instruction (MUL DX) is ?executed MOV CX, OFFFFH MOV DX, 0458H SSS: MOVAX, 0023H MUL DX INC CX JZ RRR JNCSSS RRR: HLT FFFFH times O FFFEH times () 1 time O 0 time O
Microprocessor 8086
Table Q15 shows the micro-operations of fetch cycle, interrupt cycle, and execute cycle of the ADD instruction. Note: Accumulator (AC), internal registers (Y, Z), Interrupt Service Routine (ISR) TABLE Q15 Execute cycle of ADD instruction (i.e. ADD АС, X) MAR X Clock сycle Fetch cycle Interrupt cycle T1 MAR PC MBR - PC MBR + MAR Save T2 Memory PC MBR – Memory address PC ISR Memory MBR T3 IR - MBR Y MBR T4 Z AC + Y T5 AC Z Based on Table Q15, give the micro-operations of the execute cycle of the add instruction using the immediate addressing mode (i.e. ADIM AC, X). (a) (b) Give the micro-operations of the execute cycle of the add instruction using the indirect mode (i.e. ADIN AC, X).
Suppose that the following instructions are found at the given locations in memory: 20 LDA 50 21 BRP 22 22 STO 51 50 100 51 100 Choose the contents of the registers: PC, MAR, MDR, IR, A at the end of fetch-execute cycle for instruction 22: PC MAR MDR IR A
coding
If JMP 90 instruction reside at memory location OFCDA then, the memory * location of the next instruction is OFCDC O OFCDD O OFCDA O
Describe the concept of out-of-order execution in modern CPUs and its implications for ALU instruction execution.
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Q: Compute the physical address for the specified operand in each of the following instructions. The register contents and variable are as follows: (CS)=D0A00H, (DS)=OBOOH, (SS)=0DO0H, (SI)=OFFOH, (DI)=00BOH, (BP)=00EAH and (IP)=0000H, LIST=D00FOH, AX=4020H, BX=2500H. 1) Destination operand of the instruction MOV LIST (BP+DI], AX 2) Source operand of the instruction MOV CL, [BX+200H] 3) Destination operand of the instruction MOV [DI+6400H] , DX 4) Source operand of the instruction MOV AL, [BP+SI-400H] 5) Destination operand of the instruction MOV (DI+SP] , AX Source operand of the instruction MOV CL, [SP+200H] 7) Destination operand of the instruction MOV [BX+DI+640O0H], CX 8) Source operand of the instruction MOV AL , [BP- 0200H] 9) Destination operand of the instruction MOV [SI] , AX 10) Destination operand of the instruction MOV [BX][DI]+0400H,AL 11) Source operand of the instruction MOV AX, [BP+200H] 12) Source operand of the instruction MOV AL, [SI-0100H] 13) Destination operand…
What happens when the CPU executes a load instruction that reads the byte at address 0x03d4
An interrupt is received and the CPU suspends the presently running process in order to deal with it. This is known as interrupt service. What is the reason for suspending the currently running process? As an alternative, why can't we just complete the currently running process and deal with the interruption afterwards?
Modern CPUS employ branch prediction in order to: O improve the effectiveness of register forwarding allow multiple instructions access the same register at the same time reduce the latency penalty caused by control hazard O reduce the average latency of fetching each branch instruction

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