time complexity

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Hi I need help finding the time complexity The word case scenario for the following for loop.

```java
/* Worst case scenario:
   what is the value of count for an array of size 'n' */
public static boolean linS(int[] A, int st) {
    int count = 0;
    for( int i=0; i<10; i++ ) {
        count++;
        System.out.println(count);
    }
    int idx = 0;
    while( idx<A.length ) {
        count++;
        if( A[idx] == st ) {
            break;
        }
        idx++;
    }
    return idx < A.length;
}
/* How would we describe the runtime of the above code? */
```

**Explanation:**

This Java code defines a method `linS` that performs a linear search on an array `A` to find a specific integer `st`. It first executes a simple loop 10 times, incrementing and printing a `count` variable each time. It then performs a linear search on the array `A`:

1. **Initialize `count` to 0**: This variable tracks the number of operations.

2. **First loop (constant time loop)**: 
   - Runs 10 times regardless of the size of `A`.
   - Increments the `count` and prints it.

3. **Second loop (linear search on array)**:
   - Iterates through each element of `A` from the beginning.
   - Increments `count` by 1 for each iteration.
   - Breaks the loop if `st` is found.

**Runtime Analysis:**

- **Best Case:** O(1) if `st` is found immediately.
- **Worst Case:** O(n) as the loop iterates through each element of the array `A` once until `st` is found or the end is reached.
- The first loop executes 10 times, so its runtime is constant, contributing a fixed amount of operations.
Transcribed Image Text:```java /* Worst case scenario: what is the value of count for an array of size 'n' */ public static boolean linS(int[] A, int st) { int count = 0; for( int i=0; i<10; i++ ) { count++; System.out.println(count); } int idx = 0; while( idx<A.length ) { count++; if( A[idx] == st ) { break; } idx++; } return idx < A.length; } /* How would we describe the runtime of the above code? */ ``` **Explanation:** This Java code defines a method `linS` that performs a linear search on an array `A` to find a specific integer `st`. It first executes a simple loop 10 times, incrementing and printing a `count` variable each time. It then performs a linear search on the array `A`: 1. **Initialize `count` to 0**: This variable tracks the number of operations. 2. **First loop (constant time loop)**: - Runs 10 times regardless of the size of `A`. - Increments the `count` and prints it. 3. **Second loop (linear search on array)**: - Iterates through each element of `A` from the beginning. - Increments `count` by 1 for each iteration. - Breaks the loop if `st` is found. **Runtime Analysis:** - **Best Case:** O(1) if `st` is found immediately. - **Worst Case:** O(n) as the loop iterates through each element of the array `A` once until `st` is found or the end is reached. - The first loop executes 10 times, so its runtime is constant, contributing a fixed amount of operations.
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