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Time Another important equation in the study of motion can be derived from the velocity-time graph. a. The slope of the velocity-time graph represents the object's acceleration, a. Write an expression for a in terms of vi, vf, and At. - . Replace (v v) in the formula Ad = v¡At + (vv)At with an equivalent expression derived from the result of the previous step, and write a simplified equation for Ad in terms of a, v₁, and At. The change in position, Ad, can be expressed in terms of initial position, d, and final position, dj, as Ad = d.-d. Replace Ad in the result of the previous step with this expression and solve for df.

Time Another important equation in the study of motion can be derived from the velocity-time graph. a. The slope of the velocity-time graph represents the object's acceleration, a. Write an expression for a in terms of vi, vf, and At. - . Replace (v v) in the formula Ad = v¡At + (vv)At with an equivalent expression derived from the result of the previous step, and write a simplified equation for Ad in terms of a, v₁, and At. The change in position, Ad, can be expressed in terms of initial position, d, and final position, dj, as Ad = d.-d. Replace Ad in the result of the previous step with this expression and solve for df.

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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I need help with 43 please. Algebra 2 third edition ISBN: 978-1-64626-475-9

4) 8) + 2y) ab + b²) n or reason 35. A company makes wire mesh trays by snipping squares out of tray as a polynomial. each corner of a 15 in. × 20 in. rectangular piece of mesh and folding the sides up to form a tray. Express the volume of the 36. A gardener wishes to expand his rectangular garden, which is twice as long as it is wide, by increasing the width by 2 ft and the length by 7 ft. Express the new garden area as a polynomial. 37. Use the Pythagorean theorem and the given triangle to express the square of the hypotenuse as a polynomial. C. Exercises 33 Simplify. 38. (x + y)² - (x - y)² 40. (x + 8)(3x + 2) + (x + 4)(x − 4) 15 in. x - 1 42. One of the most important equations in the study of motion relates the change in position, Ad, of an object undergoing constant accel- eration to the time interval, At; its initial velocity, v;; and its final velocity, vf. The area under the velocity-time graph represents the object's change in position, Ad. Applying the formula for the area of a trapezoid to the entire shaded region produces Ad = =1/√(√₂ + v)At. a. Write an expression for the blue rectangular area. b. Write an expression for the green triangular area. c. Show that the sum of the two areas produces the same expression da for Ad as the expression resulting from applying the formula for the area of a trapezoid. x + 3 39. (x - y)² - (x - y)(x + y) 41. (3x² - 2x + 1)(2x³x² + 5x - 2) acceleration, a = Velocity v, (t₁, v.) Velocity-Time 20 in. t₁ (V in com 43. Another important equation in the study of motion can be derived from the velocity-time graph. At Time (t₂, V₁) Vfs a. The slope of the velocity-time graph represents the object's acceleration, a. Write an expression for a in terms of vi, vf, and At. (X21 b. Replace (vƒ — v;) in the formula Ad = v¡At +(vv)At with an equivalent expression derived from the result of the previous step, and write a simplified equation for Ad in terms of a, v₁, and At. c. The change in position, Ad, can be expressed in terms of initial position, d, and final position, dƒ, as Ad = df - d. Replace Ad in the result of the previous step with this expression and solve for df. 44. A third important equation describing motion is derived using Ad = (v + v)At and the definition of Vf - Vi At (v₁ - v₁) (2+xS) t₂ a. Solve the formula defining acceleration for At. b. Replace At in the formula Ad = (v + v)At with this expression and complete the product to derive a simplified formula for the change in position in terms of a, vf, and Vi. 101567 X2A + X21.6 DO.8 LIFETIME 5.1 MULTIPLYING POLYNOMIALS
Transcribed Image Text:4) 8) + 2y) ab + b²) n or reason 35. A company makes wire mesh trays by snipping squares out of tray as a polynomial. each corner of a 15 in. × 20 in. rectangular piece of mesh and folding the sides up to form a tray. Express the volume of the 36. A gardener wishes to expand his rectangular garden, which is twice as long as it is wide, by increasing the width by 2 ft and the length by 7 ft. Express the new garden area as a polynomial. 37. Use the Pythagorean theorem and the given triangle to express the square of the hypotenuse as a polynomial. C. Exercises 33 Simplify. 38. (x + y)² - (x - y)² 40. (x + 8)(3x + 2) + (x + 4)(x − 4) 15 in. x - 1 42. One of the most important equations in the study of motion relates the change in position, Ad, of an object undergoing constant accel- eration to the time interval, At; its initial velocity, v;; and its final velocity, vf. The area under the velocity-time graph represents the object's change in position, Ad. Applying the formula for the area of a trapezoid to the entire shaded region produces Ad = =1/√(√₂ + v)At. a. Write an expression for the blue rectangular area. b. Write an expression for the green triangular area. c. Show that the sum of the two areas produces the same expression da for Ad as the expression resulting from applying the formula for the area of a trapezoid. x + 3 39. (x - y)² - (x - y)(x + y) 41. (3x² - 2x + 1)(2x³x² + 5x - 2) acceleration, a = Velocity v, (t₁, v.) Velocity-Time 20 in. t₁ (V in com 43. Another important equation in the study of motion can be derived from the velocity-time graph. At Time (t₂, V₁) Vfs a. The slope of the velocity-time graph represents the object's acceleration, a. Write an expression for a in terms of vi, vf, and At. (X21 b. Replace (vƒ — v;) in the formula Ad = v¡At +(vv)At with an equivalent expression derived from the result of the previous step, and write a simplified equation for Ad in terms of a, v₁, and At. c. The change in position, Ad, can be expressed in terms of initial position, d, and final position, dƒ, as Ad = df - d. Replace Ad in the result of the previous step with this expression and solve for df. 44. A third important equation describing motion is derived using Ad = (v + v)At and the definition of Vf - Vi At (v₁ - v₁) (2+xS) t₂ a. Solve the formula defining acceleration for At. b. Replace At in the formula Ad = (v + v)At with this expression and complete the product to derive a simplified formula for the change in position in terms of a, vf, and Vi. 101567 X2A + X21.6 DO.8 LIFETIME 5.1 MULTIPLYING POLYNOMIALS
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