Tim plans to invest money into an account that earns 4.5% and is compounded continuously. How much should he invest so that he has $10,000 after 10 years? (Round to the nearest penny.)
Tim plans to invest money into an account that earns 4.5% and is compounded continuously. How much should he invest so that he has $10,000 after 10 years? (Round to the nearest penny.)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Investment Problem: Continuous Compounding Interest**
**Problem Statement:**
Tim plans to invest money into an account that earns 4.5% interest and is compounded continuously. How much should he invest so that he has $10,000 after 10 years? (Round to the nearest penny.)
**Explanation:**
To solve this problem, we'll use the formula for continuous compounding interest:
\[ A = Pe^{rt} \]
Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (in decimal).
- \( t \) is the time in years.
- \( e \) is the base of the natural logarithm, approximately equal to 2.71828.
Given:
- \( A = 10,000 \)
- \( r = 0.045 \)
- \( t = 10 \)
The goal is to solve for \( P \):
\[ 10,000 = Pe^{0.045 \times 10} \]
\[ 10,000 = Pe^{0.45} \]
To find \( P \):
1. Calculate \( e^{0.45} \).
2. Divide both sides by the result from step 1 to isolate \( P \).
Calculate \( P \) to determine how much Tim should invest initially.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92b9fa95-2e7d-446b-a380-41f972519da6%2F106884cc-88b2-4f04-a1d5-4c0436203536%2Fx047kt5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Investment Problem: Continuous Compounding Interest**
**Problem Statement:**
Tim plans to invest money into an account that earns 4.5% interest and is compounded continuously. How much should he invest so that he has $10,000 after 10 years? (Round to the nearest penny.)
**Explanation:**
To solve this problem, we'll use the formula for continuous compounding interest:
\[ A = Pe^{rt} \]
Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (in decimal).
- \( t \) is the time in years.
- \( e \) is the base of the natural logarithm, approximately equal to 2.71828.
Given:
- \( A = 10,000 \)
- \( r = 0.045 \)
- \( t = 10 \)
The goal is to solve for \( P \):
\[ 10,000 = Pe^{0.045 \times 10} \]
\[ 10,000 = Pe^{0.45} \]
To find \( P \):
1. Calculate \( e^{0.45} \).
2. Divide both sides by the result from step 1 to isolate \( P \).
Calculate \( P \) to determine how much Tim should invest initially.
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