Can you answer the last 3 remainding and show all work and explanations please and thank you! TikTok users spend an average of 55 minutes per day using the app. A researcher believes the time spend is less among teenager users. Arandom sample of 61 TikTok teenager users resulted in a sample mean daily use of 50 minutes, and a sample standard deviation of 12.5minutes. Is there enough evidence to support the researcher's cla For Blank 1 a level of significance of 5%.The null hypothesis is: 55The alternative hypothesis is: <55The test statistic is: -3.124The critical value is:Can you reject the null hypothesis? Yes or No.State your conclusion in the context of the problem:

From the provided information, Sample size (n) = 61 Level of significance (α) = 0.05 The test is…

Answered: TikTok users spend an average of 55…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A custodian wishes to compare two competing floor waxes to decide which one is best. He believes that the mean of WaxWin is less than the mean of WaxCo. In a random sample of 20 floors of WaxWin and 17 of WaxCo. WaxWin had a mean lifetime of 26.4 with a standard deviation of 8.6 and WaxCo had a mean lifetime of 27.2 with a standard deviation of 6.6. Perform a hypothesis test using a significance level of 0.05 to help him decide. Let WaxWin be sample 1 and WaxCo be sample 2 The correct hypotheses are: Ο Ηο: μι < με HA₁₂(claim) Ο Ηρ: με 2 με HA: 1₂(claim) O Ho: ₁ = ₂ HAM12(claim) Since the level of significance is 0.05 the critical value is -1.69 (round to 3 places) The test statistic is: The p-value is: (round to 3 places)
You may need to use the appropriate technology to answer this question. Is there any difference in the variability in golf scores for players on a women's professional golf tour and players on a men's professional golf tour? A sample of 20 tournament scores from events in a tour for women showeda standard deviation of 2.4687 strokes, and a sample of 30 tournament scores from events in a tour for men showed a standard deviation of 2.2121. Conduct a hypothesis test for equal population variances to determine if there is any statistically significant difference in the variability of golf scores for male and female professional golfers. Use a = 0.10. State the null and alternative hypotheses. O Ho: H: 0,2 = o Ho: o, Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. O Reject Ho: We can conclude that there is a difference in the variability of golf scores for male and…
A custodian wishes to compare two competing floor waxes to decide which one is best. He believes that the mean of WaxWin is less than the mean of WaxCo. In a random sample of 18 floors of WaxWin and 10 of WaxCo. WaxWin had a mean lifetime of 22.1 with a standard deviation of 5.6 and WaxCo had a mean lifetime of 28.5 with a standard deviation of 7.1. Perform a hypothesis test using a significance level of 0.05 to help him decide. Let WaxWin be sample 1 and WaxCo be sample 2 The correct hypotheses are: O Ho: H1 µ2(claim) O Ho: µ1 2 H2 HA: H1 < µ2(claim) O Ho: µ1 = µ2 HA: H1 7 M2(claim) Since the level of significance is 0.05 the critical value is -1.751 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: O There is enough evidence to reject the claim that the mean of WaxWin is less than the mean of WaxCo. O There is not enough evidence to reject the claim that the mean of…
A custodian wishes to compare two competing floor waxes to decide which one is best. He believes that the mean of WaxWin is not equal to the mean of WaxCo. In a random sample of 12 floors of WaxWin and 20 of WaxCo. WaxWin had a mean lifetime of 27.6 with a standard deviation of 8.8 and WaxCo had a mean lifetime of 20.3 with a standard deviation of 7.6. Perform a hypothesis test using a significance level of 0.01 to help him decide. Let WaxWin be sample 1 and WaxCo be sample 2 The correct hypotheses are: HA: P1 > µ2(claim) Ho: µ1 2 µ2 HA: µ1 < µ2(claim) Ho: µ1 = µ2 HA: H1 + H2(claim) Since the level of significance is 0.01 the critical value is 2.836 and -2.836 The test statistic is: (round to 3 places) The p-value is: (round to 3 places)
Devise a null and alternative hypothesis then perform a one sample z-test using alpha 0.05 if the class is shorter or taller than the average human in the United States. Graphically display your answer and statistically write up the results. United States average is 67 +/- 3.8 inches. The class mean is 69 inches and the class standard deviation is 5.9 inches. The class sample size is 21 students.
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You may need to use the appropriate technology to answer this question. Is there any difference in the variability in golf scores for players on a women's professional golf tour and players on a men's professional golf tour? A sample of 20 tournament scores from events in a tour for women showed a standard deviation of 2.4671 strokes, and a sample of 30 tournament scores from events in a tour for men showed a standard deviation of 2.2182. Conduct a hypothesis test for equal population variances to determine if there is any statistically significant difference in the variability of golf scores for male and female professional golfers. Use a = 0.10. State the null and alternative hypotheses. Ho: Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. O Reject Ho. We cannot conclude that there is a difference in the variability of golf scores for male and female…
The mean BMI in patients free of diabetes has been reported as 27.8. An investigator measured BMI in 12 patients who are free of diabetes and found a mean BMI of 30.2 with a standard deviation of 5.5. The investigator hypothesizes that the BMI in patients free of diabetes is higher than what has been reported. Is there evidence that the BMI is significantly higher that 27.8? Use a 5% level of significance. Give each of the following to receive full credit: 1) the appropriate null and alternative hypotheses; 2) the appropriate test; 3) the decision rule; 4) the calculation of the test statistic; and 5) your conclusion including a comparison to alpha or the critical value. You MUSTshow your work to receive full credit. Partial credit is available.
20 TV remote controls were followed over the years to find the mean lifespan of this model. The sample gave a mean of 7.2 years, and the standard deviation of 0.6 years. The distribution of the population is unknown. Construct a 90% confidence interval for the mean lifespan of these remote controls.
A2.2
A manufacturer of sports equipment has developed a new synthetic fishing line that he claims has a mean breaking strength of 8 kilograms with a standard deviation of 0.5 kilogram. Test the hypothesis that ? = ? kilograms against the alternative hypothesis ? ≠ ? kilograms if a random sample of 50 lines is tested and found to have a mean breaking strength of 7.8 kilograms. Use a 0.01 level of significance. Step 1: Null and Alternative HypothesisHo: Ha: Step 2: Level of Significance and appropriate test statistic Step 3: Determine the Critical RegionCritical Region: Step 4: Compute the z or t value Step 5: Decide whether to accept or reject Ho. Step 6: Conclusion
An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 3939 type K batteries and a sample of 5757 type Q batteries. The mean voltage is measured as 8.558.55 for the type K batteries with a standard deviation of 0.6830.683, and the mean voltage is 8.828.82 for type Q batteries with a standard deviation of 0.7910.791. Conduct a hypothesis test for the conjecture that the mean voltage for these two types of batteries is different. Let μ1μ1 be the true mean voltage for type K batteries and μ2μ2 be the true mean voltage for type Q batteries. Use a 0.020.02 level of significance. Step 3 of 4 : Determine the decision rule for rejecting the null hypothesis H0H0. Round the numerical portion of your answer to two decimal places

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