Thus, for u = g(x) = sin(5x), %3! f'(g(x)) = F'(sin(5x)) = 8 %3D %3D 8 Next we calculate g'(x). g(x) = sin(5x) %3! gʻ(x) = 5 cos(5x) 5 cos (5r) g'(x) = Step 3 of 3 Applying the chain rule, find the derivative of (fo g) where f(u) = 8u +1 and g(x) = sin(5x) with %3D f'(g(x)) = 8 and g'(x) = 5 cos 5x). %3D (f o g)'(x) = f'(g(x)}g'(x).

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