th's magnetic A) 22 μT T-Attenuat Ba anometer has K-0.1A, N-50 and a-5cm, the horizontal comp field Bo is (uo-4mx10 T.m/A): B) 52 µT C) 45 pT D) 39 T EJ 62 µT
th's magnetic A) 22 μT T-Attenuat Ba anometer has K-0.1A, N-50 and a-5cm, the horizontal comp field Bo is (uo-4mx10 T.m/A): B) 52 µT C) 45 pT D) 39 T EJ 62 µT
Related questions
Question
Q1
Transcribed Image Text:the tangent galvanometer has K-0.1A, N-50 and a-5cm, the horizontal compu
Earth's magnetic field Bo is (uo-4x10T.m/A):
A) 22 µT
B) 52 µT
C) 45 pT
D) 39 T EJ 62 µT
T-Attenuator: (Q14, Q15, Q16)
214) If the attenuation factor N-0.2, RL-4000 and e=10 volts, the current passing throu
the load resistance is:
A) 0.005 A
B) 0.004 A
C) 0.006 A
D) 0.008 A
E) 0.02 A
Q15) The equivalent resistance in the previous circuit is:
A) 5000
B) 2000
C) 2500
D) 4000
E) 1000
Q16) The suggested attenuation factor N if the output voltage across R, becomes 2V is:
A) 1.5
B) 3.5
C) 4
D) 0.3
E) 5
The Wheatstone Bridge: (Q17, Q18)
17) The figure shows Wheatstone bridge at equilibrium given that E-SV, R= 200, L₁4
and R2-10, then R. equals
A) 40
B) 3.70
C) 8.50
D) 1.20
E) 60
160
Q18) According to the figure in the previous question, if
E=5V, then IG equals:
www.
www.w
R
Rat
6 Ohms R
A) Zero
B) 1.5A
E) 9A
C) 3A
D) 6A
Electric Power: (Q19, Q20)
Q19: A load resistance R, is connected in series to two resistors R₁-120 and R-100 and
power supply with E=25V, then the maximum power dissipated in R, in Watts equals:
E) 10
B) 2.1
C) 6.4 D) 7.1
A) 5
D120
Q20: If R₁ 200 02, i=0.5A and E-50V, the voltage across R, in Volts when P is maximum
El 25
A) 5
C) 15
B) 10
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