Three vectors are given as: À = 3â – 9ỹ - B = 7âx + 10âŷ C = 4â + 5ŷ + 6£ These three vectors are used to define a parallelepiped. (a) What is the volume of the parallelepiped? (b) What is the surface area of the parallelepiped?

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Chapter1: Units, Trigonometry. And Vectors
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Three vectors are given as:
A = 3â – 9âỹ
B = 7ââ + 10ŷ
C = 4⣠+ 5ÿ+ 62
These three vectors are used to define a parallelepiped.
(a) What is the volume of the parallelepiped?
(b) What is the surface area of the parallelepiped?
Transcribed Image Text:Three vectors are given as: A = 3â – 9âỹ B = 7ââ + 10ŷ C = 4⣠+ 5ÿ+ 62 These three vectors are used to define a parallelepiped. (a) What is the volume of the parallelepiped? (b) What is the surface area of the parallelepiped?
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Step 1

Given-

A = 3x^ - 9y^B = 7x^ + 10y^C = 4x^ + 5y^+6z^

 

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