Three simple curves are connected to each other such that the first and the second form a compound curve while the second and the third formed a reversed curve. The distance between the point of curvature and the point of tangency of the compound curve which is also the point of reversed curvature of the reversed curve is 485.025 meters. If the angle of convergence between the second and the third tangents is 15° I, = 45°, R; = 190.986 m., I2 = 60°, R3 = 159.155 m. and stationing at P.C. is 0 + 520. (a) Determine the stationing at P.T. at the end of the long chord. (b) Determine the angle between the long chord of the compound curve and the first tangent in deg-min-sec. (c) Determine the angle between the long chord of the compound curve and the second tangent in deg-min-sec.
Three simple curves are connected to each other such that the first and the second form a compound curve while the second and the third formed a reversed curve. The distance between the point of curvature and the point of tangency of the compound curve which is also the point of reversed curvature of the reversed curve is 485.025 meters. If the angle of convergence between the second and the third tangents is 15° I, = 45°, R; = 190.986 m., I2 = 60°, R3 = 159.155 m. and stationing at P.C. is 0 + 520. (a) Determine the stationing at P.T. at the end of the long chord. (b) Determine the angle between the long chord of the compound curve and the first tangent in deg-min-sec. (c) Determine the angle between the long chord of the compound curve and the second tangent in deg-min-sec.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Three simple curves are connected to each other such that the first and the second form a compound
curve while the second and the third formed a reversed curve. The distance between the point of
curvature and the point of tangency of the compound curve which is also the point of reversed
curvature of the reversed curve is 485.025 meters. If the angle of convergence between the second
and the third tangents is 15° I, = 45°, R; = 190.986 m., I2 = 60°, R3 = 159.155 m. and stationing at P.C.
is 0 + 520. (a) Determine the stationing at P.T. at the end of the long chord. (b) Determine the angle
between the long chord of the compound curve and the first tangent in deg-min-sec. (c) Determine the
angle between the long chord of the compound curve and the second tangent in deg-min-sec.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc835e28a-2f21-4de4-b135-8dfa70be8f67%2Fb3f306ff-57b5-4a21-ba58-0a591ac3bd28%2F7anrefr_processed.png&w=3840&q=75)
Transcribed Image Text:Three simple curves are connected to each other such that the first and the second form a compound
curve while the second and the third formed a reversed curve. The distance between the point of
curvature and the point of tangency of the compound curve which is also the point of reversed
curvature of the reversed curve is 485.025 meters. If the angle of convergence between the second
and the third tangents is 15° I, = 45°, R; = 190.986 m., I2 = 60°, R3 = 159.155 m. and stationing at P.C.
is 0 + 520. (a) Determine the stationing at P.T. at the end of the long chord. (b) Determine the angle
between the long chord of the compound curve and the first tangent in deg-min-sec. (c) Determine the
angle between the long chord of the compound curve and the second tangent in deg-min-sec.
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