Three research departments have 6, 10, and 9 members, respectively. Each department is to select a delegate and an alternate to represent the department at a conference. In how many ways can this be done?

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Permutations, combinations, and the multiplication principle for...
Three research departments have 6, 10, and 9 members, respectively.
Each department is to select a delegate and an alternate to represent
the department at a conference. In how many ways can this be done?
(If necessary, consult a list of formulas.)
圖
Explanation
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Expert Solution
Step 1

Given 3 research department having members 6, 10 and 9 respectively.

We are about to chose a delegate and an alternative from each department.

By using permutations, the number of ways

P26×P210×P29 =6!(6-2)!×10!(10-2)!×9!(9-2)!                        =30 × 90×72                        =194400

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