Three different objects, all with different masses, are initially at rest at the bottom of a set of steps. Each step is of uniform height d. The mass of each object is a multiple of the base mass m: object 1 has mass 3.10m, object 2 has mass 1.46m, and object 3 has mass m. When the objects are at the bottom of the steps, define the total gravitational potential energy of the three-object system to be zero. If the objects are then relocated as shown, what is the new total potential energy of the system? Each answer requires the numerical coefficient to an algebraic expression. Each algebraic expression is given using some combination of the variables m, g, and d, where g is the acceleration due to gravity. Enter only the numerical coefficient. (Example: If the answer is 1.23mgd, just enter 1.23)
Three different objects, all with different masses, are initially at rest at the bottom of a set of steps. Each step is of uniform height d. The mass of each object is a multiple of the base mass m: object 1 has mass 3.10m, object 2 has mass 1.46m, and object 3 has mass m. When the objects are at the bottom of the steps, define the total gravitational potential energy of the three-object system to be zero. If the objects are then relocated as shown, what is the new total potential energy of the system? Each answer requires the numerical coefficient to an algebraic expression. Each algebraic expression is given using some combination of the variables m, g, and d, where g is the acceleration due to gravity. Enter only the numerical coefficient. (Example: If the answer is 1.23mgd, just enter 1.23)
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Now, find a new reference height (measured again from the bottom of the stairs) such that the highest two objects have the exact same potential energy.
The answer was not 0.082 or the negative of that, I tried both and no luck. Both were marked wrong.
Transcribed Image Text:13.22
mgd
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´g,system
You have not correctly solved for the
reference height at which the highest
This potential energy was calculated relative to the bottom
of the stairs. If you were to redefine the reference height
two objects have the exact same
potential energy.-
such that the total potential energy of the system became
zero, how high above the bottom of the stairs would the
Check your algebra carefully. For the
new reference height be?
reference height you have entered,
the more massive object also has the
greatest height and therefore has a
much higher potential energy.
2.38
d
Now, find a new reference height (measured again from the
bottom of the stairs) such that the highest two objects
have the exact same potential energy.
-0.082
d
Incorrect
Transcribed Image Text:Three different objects, all with different masses, are
initially at rest at the bottom of a set of steps. Each step is
of uniform height d. The mass of each object is a multiple
of the base mass m: object 1 has mass 3.10m, object 2 has
mass 1.46m, and object 3 has mass m. When the objects
are at the bottom of the steps, define the total gravitational
potential energy of the three-object system to be zero. If
the objects are then relocated as shown, what is the new
total potential energy of the system?
d
Each answer requires the numerical coefficient to an
3
algebraic expression. Each algebraic expression is given
using some combination of the variables m, g, and d,
where g is the acceleration due to gravity. Enter only the
numerical coefficient. (Example: If the answer is 1.23mgd,
just enter 1.23)
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