Three Concrete Slabs. Suppose there are three concrete rectangular slabs standing or resting on level ground in the order that is depicted in the diagram below. The angle of depression from Slab 2 to Slab 1 is 22°and they are 8 feet apart. Slab 3 is leaning on Slab 2 making an angle of 40° with a vertical reference line. Find the height of Slab 2 and the length of Slab 3. 40 Slab 3 Slab 2 22 Slab1 2ft -Level Ground 8ft

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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**Three Concrete Slabs: Explanation and Problem**

Suppose there are three concrete rectangular slabs standing or resting on level ground in the order depicted in the diagram. The angle of depression from Slab 2 to Slab 1 is \(22^\circ\) and they are 8 feet apart. Slab 3 is leaning on Slab 2, making an angle of \(40^\circ\) with a vertical reference line.

**Objective:**
Find the height of Slab 2 and the length of Slab 3.

**Diagram Details:**

- **Slab 1** is a rectangular slab resting on the ground with its height not specified but a horizontal distance to Slab 2 of 2 feet.
- **Slab 2** is a vertical rectangular slab whose height needs to be determined.
- **Slab 3** is leaning against Slab 2, forming a \(40^\circ\) angle with the vertical.

**Distances and Angles:**

- The base between Slab 2 and Slab 1 is 8 feet.
- Vertical angle at Slab 2 towards Slab 1 is \(22^\circ\).
- Slab 3 makes a \(40^\circ\) angle with the vertical.

**Solution Steps:**

- Use trigonometric identities to calculate the height of Slab 2.
- Use trigonometric identities to calculate the length of Slab 3 based on its angle with the vertical.

The actual trigonometric calculations involve using tangent, sine, and cosine as appropriate based on the given angles to solve for the unknown lengths.
Transcribed Image Text:**Three Concrete Slabs: Explanation and Problem** Suppose there are three concrete rectangular slabs standing or resting on level ground in the order depicted in the diagram. The angle of depression from Slab 2 to Slab 1 is \(22^\circ\) and they are 8 feet apart. Slab 3 is leaning on Slab 2, making an angle of \(40^\circ\) with a vertical reference line. **Objective:** Find the height of Slab 2 and the length of Slab 3. **Diagram Details:** - **Slab 1** is a rectangular slab resting on the ground with its height not specified but a horizontal distance to Slab 2 of 2 feet. - **Slab 2** is a vertical rectangular slab whose height needs to be determined. - **Slab 3** is leaning against Slab 2, forming a \(40^\circ\) angle with the vertical. **Distances and Angles:** - The base between Slab 2 and Slab 1 is 8 feet. - Vertical angle at Slab 2 towards Slab 1 is \(22^\circ\). - Slab 3 makes a \(40^\circ\) angle with the vertical. **Solution Steps:** - Use trigonometric identities to calculate the height of Slab 2. - Use trigonometric identities to calculate the length of Slab 3 based on its angle with the vertical. The actual trigonometric calculations involve using tangent, sine, and cosine as appropriate based on the given angles to solve for the unknown lengths.
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