Three coils each having resistance of 3 Q and capacitive reactance of 4 Q are connected in delta to A7 415V, 50HZ, 3 phase supply. The power factor is (а) 0.60 (b) 0.80 (c) 0.75 (d) 0.99 A 1000 V/440 V, single-phase transformer takes a no-load current of 0.6 A and the iron loss is 300 W. A8 The core loss component of the no-load current (Iw) is , A (а) 0.2 (b) 0.68 (c) 1.14 (d) 0.3

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Three coils each having resistance of 3 Q and capacitive reactance of 4 Q are connected in delta to
A7
415V, 50HZ, 3 phase supply. The power factor is,
(а) 0.60
(b) 0.80
(c) 0.75
(d) 0.99
A 1000 V/440 V, single-phase transformer takes a no-load current of 0.6 A and the iron loss is 300 W.
A8
The core loss component of the no-load current (Iw) is
A
(a) 0.2
(b) 0.68
(c) 1.14
(d) 0.3
Transcribed Image Text:Three coils each having resistance of 3 Q and capacitive reactance of 4 Q are connected in delta to A7 415V, 50HZ, 3 phase supply. The power factor is, (а) 0.60 (b) 0.80 (c) 0.75 (d) 0.99 A 1000 V/440 V, single-phase transformer takes a no-load current of 0.6 A and the iron loss is 300 W. A8 The core loss component of the no-load current (Iw) is A (a) 0.2 (b) 0.68 (c) 1.14 (d) 0.3
Expert Solution
Step 1

According to question:

A7) Power factor is calculated as

ZP=R-jXCZP=3-j4ZP=5-53.130ΩIP=VPZPIP=415005-53.130IP=8353.130Apf=cosϕv-ϕipf=cos00-530pf=cos-530pf=0.6

Step 2

A8) The core loss component of I0 is calculated as

Pi=VIwIw=PiVAs no load test is done on LV side,V=440VIw=300440Iw=0.68A

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