Can you help me answer this? And explain why of 1200 V, it gains 1200 eV of kinetic energy. Using the known charge on anelectron, it is easy to see that 1 eV = 1.6 x 10-9 I. Thus, 1200 eV = 1.92 x10-1 J. Using the known mass of the electron (9.1 x 10-3 kg), we can deter-mine the velocity of electrons in these devices. In our example:1.92 x 10 "J=9.1x10x10kg)v²andv= 2.05 x 10 m/sMisconceptionsIt is important to remember that the potential difference (or voltage) is ameasure of the work done per charge (APE/q) in units of J/C or volts.This is the essence of the battery, which stores potential difference usingtwo different metals (such as lead and zinc) and an acid to produce anelectrochemical reaction. We will not go into the details of the chemistryinvolved in battery design here.162Easy Physics Step-by-StepFinally, we do not have space to go into all details of electrostatics, butyou should know that a simple device for storing static charges (using thedesign of parallel plates and an insulating material known as a dielectric)is called a capacitor. Capacitors play a very important role in advancedcircuits, but we will be discussing only simple electric circuits in the nextchapter. The capacitor is quantified by its capacitance, C (its ability to storecharge when connected to a voltage source), in units of farads (F) such thatC = q/VMore information about capacitors can be found in more advanced phys-ics books.Problem-Solving Strategies to Avoid MisstepsAs you solve problems with electrostatic forces and fields, it is always impor-tant to remember (as we have repeated many times) that Coulomb's Law isan inverse square law. This means you must make sure not only to use thecorrect units but to remember the force varies inversely with the square ofthe distance between the two charges. Additionally, even if you have elec-trons moving in free space, the direction of the electric field is the directionthat a positive test charge would go. Finally, the voltage source is referred toas a source of potential difference equal to the work done per unit coulombof charge (1 C = 6.25 x 10" elementary charges). The problem-solving ring isalways available for you to consult as you plan a problem-solving strategy.Exercise 14.11. Three charges are arranged along a line. On the left, a charge (A) of 7.0x 10- C is fixed. A second charge (B) of -2.0 x 10- C is located 0.5 mto the right of charge A. Finaly, a third fixed charge (C) of 3.0 x 104 C islocated 0.3 m from charge B. Calculate the net force acting on charge Bdue to the two fixed charges.2. A proton is accelerated from rest by a potential difference of 800 Vbetween two parallel plates. Calculate the kinetic energy gained by theproton in units of eV and joules. Using the known mass of a proton (1.67x 10-7 kg), calculate the velocity gained by the proton.

Answered: Image /qna-images/answer/9038d999-e5d6-481d-a3ff-be53ae5f3016.jpg

Three charges are arranged along a line. On the left, a charge (A) of 7.0 x 10C is fixed. A second charge (B) of -2.0 x 10C is located 0.5 m to the right of charge A. Finally, a third fixed charge (C) of 3.0 x 10 C is located 0.3 m from charge B. Calculate the net force acting on charge B due to the two fixed charges.