Three capacitors of capacitance C1 = 1.35 µF, C2 = 3.95 µF, and C3 = 4.20 µF are connected in series. A %3D potential difference of AVb = 94.0 V is maintained by a battery. %3D Find the equivalent capacitance of the series of capacitors and the charge on each capacitor. Сед Did you accidentally divide or take the inverse in your calculation? µF Q = µč Determine the effect on the equivalent capacitance of reducing the second capacitance to 0.1 times its previous value. Ceq µF

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Q: a be ㅏ C5 ㅔ = C2 C4 ㅏ

A: C1 = C5 = 8.5 μF  C2 = C3 = C4 = 4.7 μF

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Q: HH HH a. 2.4 uF b. 2.12 juF . 0.42 juF d. 0.17 uF

A: Given data: The magnitude of each capacitance is C=4 μF.

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A: Given: C1=9.8μF C2=4.6μF C3=4.8μF

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Combination of Capacitors

The connection of capacitors can be established in a circuit in two ways.