Three blocks are connected by a weightless cord and rest on an inclined plane (Fig. 2(a)). The following set of simultaneous equations is derived from the free- body diagrams shown in Fig. 2(b): 100a +T + (0)R =519.72 50a -T +R=216.55 25a + (0)T – R =108.27 Without interchanging the rows and columns, solve for the acceleration a and the tensions T and R, in the two ropes by using Gauss-Seidel iteration method. Stop all calculations after three iterations. 25 kg 50 kg 100 kg 45° 692.96 x 0.25- 173.24 692.96 692.96 346,48 173 24 x 0.375 s 173.24 100 x 9.8 = 980 173.24 346.48 50 X'9,8 = 490 25 x9.8 a, acceleration 0,375 129.93
Three blocks are connected by a weightless cord and rest on an inclined plane (Fig. 2(a)). The following set of simultaneous equations is derived from the free- body diagrams shown in Fig. 2(b): 100a +T + (0)R =519.72 50a -T +R=216.55 25a + (0)T – R =108.27 Without interchanging the rows and columns, solve for the acceleration a and the tensions T and R, in the two ropes by using Gauss-Seidel iteration method. Stop all calculations after three iterations. 25 kg 50 kg 100 kg 45° 692.96 x 0.25- 173.24 692.96 692.96 346,48 173 24 x 0.375 s 173.24 100 x 9.8 = 980 173.24 346.48 50 X'9,8 = 490 25 x9.8 a, acceleration 0,375 129.93
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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![2. Three blocks are connected by a weightless cord and rest on an inclined plane
(Fig. 2(a)). The following set of simultaneous equations is derived from the free-
body diagrams shown in Fig. 2(b):
100a +T + (0)R = 519.72
50a -T +R=216.55
25a + (0)T – R =108.27
Without interchanging the rows and columns, solve for the acceleration a and the
tensions T and R, in the two ropes by using Gauss-Seidel iteration method. Stop all
calculations after three iterations.
25 kg
50 kg
100 kg
45
1346 48 × 0,375 - 129.93
346.48
173 24 x 0.375 - 64.97
173,24
346,48
692.96
100 x 9.8 = 980
50
9,8 490
25 x 98- 245
a, acceleration
96769
T692.96 x 0.25 = 173.24
173.24](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F85fe6772-a680-4b83-96e6-10d77424b6b6%2Fd267fe8f-62f2-4021-84b2-416c8da24534%2Ffajkqqw_processed.png&w=3840&q=75)
Transcribed Image Text:2. Three blocks are connected by a weightless cord and rest on an inclined plane
(Fig. 2(a)). The following set of simultaneous equations is derived from the free-
body diagrams shown in Fig. 2(b):
100a +T + (0)R = 519.72
50a -T +R=216.55
25a + (0)T – R =108.27
Without interchanging the rows and columns, solve for the acceleration a and the
tensions T and R, in the two ropes by using Gauss-Seidel iteration method. Stop all
calculations after three iterations.
25 kg
50 kg
100 kg
45
1346 48 × 0,375 - 129.93
346.48
173 24 x 0.375 - 64.97
173,24
346,48
692.96
100 x 9.8 = 980
50
9,8 490
25 x 98- 245
a, acceleration
96769
T692.96 x 0.25 = 173.24
173.24
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