Those data are forquestions 12.13& 14. The slender 8-kg bar AB is horizontal and at rest. The spring has an unstretched length so of 1 m and a spring constant of 15 N/m. the length of the bar AB is l-1.5m Find the elastic energy due to the spring when the bar has rotate clockwise 0 - 45° after being released. Give your answer with 2 decimals.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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**Problem Statement for Educational Website**

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**Topic: Elastic Energy in Rotational Systems**

**Scenario:**

The given data corresponds to questions 12, 13, and 14. We have an 8-kg slender bar AB that is initially horizontal and at rest. A spring is attached to the bar. The spring has an unstretched length (\(s_0\)) of 1 meter and a spring constant (\(k\)) of 15 N/m. The entire length of the bar AB (\(l\)) is 1.5 meters.

**Objective:**

Determine the elastic energy stored in the spring once the bar has rotated by an angle \(\theta = 45^\circ\) clockwise from its initial position. The answer should be rounded to two decimal places.

**Diagram Description:**

A diagram illustrates the setup:

- The bar \(AB\) is extended horizontally with point \(A\) attached to a fixed wall.
- Point \(B\) is connected to a spring, which is anchored vertically above point \(B\).
- The spring is shown in a vertical orientation, with its natural length labeled as \(s_0\).
- The spring is extended or compressed as the bar rotates, indicated by a change in its length in the diagram.

**Problem Solving Approach:**

To find the elastic energy, use the formula for elastic potential energy in a spring:

\[ Ee = \frac{1}{2} k (s - s_0)^2 \]

Where \(s\) is the new length of the spring after rotation. Calculate \(s\) using the components of the motion as the bar rotates \(45^\circ\).

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This explanation is structured to guide students through understanding the problem setup, objectives, and steps necessary to solve for the elastic energy within a physical rotational system.
Transcribed Image Text:**Problem Statement for Educational Website** --- **Topic: Elastic Energy in Rotational Systems** **Scenario:** The given data corresponds to questions 12, 13, and 14. We have an 8-kg slender bar AB that is initially horizontal and at rest. A spring is attached to the bar. The spring has an unstretched length (\(s_0\)) of 1 meter and a spring constant (\(k\)) of 15 N/m. The entire length of the bar AB (\(l\)) is 1.5 meters. **Objective:** Determine the elastic energy stored in the spring once the bar has rotated by an angle \(\theta = 45^\circ\) clockwise from its initial position. The answer should be rounded to two decimal places. **Diagram Description:** A diagram illustrates the setup: - The bar \(AB\) is extended horizontally with point \(A\) attached to a fixed wall. - Point \(B\) is connected to a spring, which is anchored vertically above point \(B\). - The spring is shown in a vertical orientation, with its natural length labeled as \(s_0\). - The spring is extended or compressed as the bar rotates, indicated by a change in its length in the diagram. **Problem Solving Approach:** To find the elastic energy, use the formula for elastic potential energy in a spring: \[ Ee = \frac{1}{2} k (s - s_0)^2 \] Where \(s\) is the new length of the spring after rotation. Calculate \(s\) using the components of the motion as the bar rotates \(45^\circ\). --- This explanation is structured to guide students through understanding the problem setup, objectives, and steps necessary to solve for the elastic energy within a physical rotational system.
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