Thm 1.22. a- Let f be continuous at a, 1. If f (a) > k, then 3 8 > 0 such that: ]x - al < 8 = f(x) > k 2. If f (a) < k, then 3 8 > 0 such that: x- a| < 8 = f(x)< k b- Let f be continuous from the right at a, 1. If f (a) > k, then 3 8 > 0 such that: a k 2. If f (a) < k, then 3 8 > 0 such that: a < x< a+ 8 = f(x) k, then 3 8 > 0 such that: a – 8 < x < a = f(x) >k 2. If f (a) < k, then 3 8 > 0 such that: a -8

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