This sphere has a diameter of 20 feet. The center of the sphere is 12 ft from the ground. (x – 0)² + (y – 0)² + (z – 12)² = 10² x² + y? + (z – 12)² = 100 center of sphere is (0,0,12) 100 –x² 100 – x 2 2 ~10 c12+V_100 -X-V =L10 LV100 - J12-V 100 –x²- 7 dzdydx 100 -x -y

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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find the volume of the sphere in cubic feet

This sphere has a diameter of 20 feet. The center of the sphere is 12 ft from the
ground.
(x – 0)² + (y – 0)² + (z – 12)² = 10²
x² + y? + (z – 12)² = 100
center of sphere is (0,0,12)
100 –x²
100 – x
2
2
r10
c12+V_100
=So LI100 - S12-V 100 –x²-
-X -V
100 -x -y
7 dzdydx
Transcribed Image Text:This sphere has a diameter of 20 feet. The center of the sphere is 12 ft from the ground. (x – 0)² + (y – 0)² + (z – 12)² = 10² x² + y? + (z – 12)² = 100 center of sphere is (0,0,12) 100 –x² 100 – x 2 2 r10 c12+V_100 =So LI100 - S12-V 100 –x²- -X -V 100 -x -y 7 dzdydx
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