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This solution is giving me error and you can add x310A that is out of range ORIG x3000 LEA R2, xFF ; R2 = x3000 + x1 + xFF = x3100 start of data LDR R3, R2, x0 ; R3 = value from address present in R2+0 Loop: NOT R4, R3 ; R4 = NOT R3 ADD R4, R4, #1 ; R4 = R4 + 1, find 2's complement of 5

This solution is giving me error and you can add x310A that is out of range ORIG x3000 LEA R2, xFF ; R2 = x3000 + x1 + xFF = x3100 start of data LDR R3, R2, x0 ; R3 = value from address present in R2+0 Loop: NOT R4, R3 ; R4 = NOT R3 ADD R4, R4, #1 ; R4 = R4 + 1, find 2's complement of 5

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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This solution is giving me error and you can add x310A that is out of range

ORIG x3000

LEA R2, xFF ; R2 = x3000 + x1 + xFF = x3100 start of data

LDR R3, R2, x0 ; R3 = value from address present in R2+0

Loop:

NOT R4, R3 ; R4 = NOT R3

ADD R4, R4, #1 ; R4 = R4 + 1, find 2's complement of 5

ADD R4, R4, #5 ; R4 = R4 + 5

BRZ Found ; if result is zero, goto label Found

LDR R3, R2, x1 ; R3 = value from address present in R2+0

NOT R4, R2 ; R4 = Not R2

ADD R4, R4, #1 ; R4 = R4 + 1, find 2's complement

ADD R4, R4, x310A ; R4 = R4 + x310A, check if last memory crossed

BRZ End; if yes then goto label End

BR Loop ; else goto Loop

 

Found:

ADD R5, R5, #1 ; found hence R5 = 1

End:

END ; end of the program

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