This reaction represents the titration from today's lab. 2 S₂0₂² + 1₂ → S406² +21 In this reaction, [Select] ✓ [Select] S406 1- 12 S203 ◆ is the oxidizing agent and is the reducing agent.
This reaction represents the titration from today's lab. 2 S₂0₂² + 1₂ → S406² +21 In this reaction, [Select] ✓ [Select] S406 1- 12 S203 ◆ is the oxidizing agent and is the reducing agent.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter19: The Chemistry Of The Main-group Elements
Section: Chapter Questions
Problem 44QRT
Related questions
Question
![This reaction represents the titration from today's lab.
2-
2 S₂03² + 1₂ → S406² +21
O
In this reaction, [Select]
✓ [Select]
S406
1-
12
S203
is the oxidizing agent and
is the reducing agent.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F80adb728-6954-4f8d-9107-41647af52006%2Fffc133d2-db1a-403b-a4fb-8ee02c55a34b%2Fecz864_processed.jpeg&w=3840&q=75)
Transcribed Image Text:This reaction represents the titration from today's lab.
2-
2 S₂03² + 1₂ → S406² +21
O
In this reaction, [Select]
✓ [Select]
S406
1-
12
S203
is the oxidizing agent and
is the reducing agent.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
2 S2O32- + I2 -----> S4O62- + 2I-
-> Oxidizing agent is agent which has Oxidation state decreases.
-> Reducing agent is agent which has Oxidation state increases.
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Solved in 2 steps with 1 images
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