This question is about the function f(8) = (0 – 3) cos(@). (a) Explain why the graph of f lies on or above the 0-axis for all values of 0 in the interval [37/2,5/2]. (b) Write down an expression, involving a definite integral, that gives the area between the graph of f and the 0-axis, from 0 = 37/2 to 0 = 5x/2. (c) Use integration by parts to find the area described in part (b), giving both the exact answer and an approximation to three decimal places.
This question is about the function f(8) = (0 – 3) cos(@). (a) Explain why the graph of f lies on or above the 0-axis for all values of 0 in the interval [37/2,5/2]. (b) Write down an expression, involving a definite integral, that gives the area between the graph of f and the 0-axis, from 0 = 37/2 to 0 = 5x/2. (c) Use integration by parts to find the area described in part (b), giving both the exact answer and an approximation to three decimal places.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 21T
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![This question is about the function
f(0) = (0 – 3) cos(@).
(a) Explain why the graph of f lies on or above the 0-axis for all values of 0
in the interval [37/2, 57/2].
(b) Write down an expression, involving a definite integral, that gives the
area between the graph of f and the 6-axis, from 0 = 37/2 to 0 = 57/2.
(c) Use integration by parts to find the area described in part (b), giving
both the exact answer and an approximation to three decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8697d872-037d-4e6f-a9fa-7be101359613%2F9a4b6090-0330-48ec-acb7-e58753143824%2F9j0l38f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:This question is about the function
f(0) = (0 – 3) cos(@).
(a) Explain why the graph of f lies on or above the 0-axis for all values of 0
in the interval [37/2, 57/2].
(b) Write down an expression, involving a definite integral, that gives the
area between the graph of f and the 6-axis, from 0 = 37/2 to 0 = 57/2.
(c) Use integration by parts to find the area described in part (b), giving
both the exact answer and an approximation to three decimal places.
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