This question is about stack implementation. Translate the VM command "push constant 10″ into hack symbolic assembly code. (Hint: the corresponding hack pseudo-code is: *SP = 10; SP++).
This question is about stack implementation. Translate the VM command "push constant 10″ into hack symbolic assembly code. (Hint: the corresponding hack pseudo-code is: *SP = 10; SP++).
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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computer fundamental-hack assembly language
![d. This question is about stack implementation. Translate the VM command
"push constant 10" into hack symbolic assembly code. (Hint: the
corresponding hack pseudo-code is: *SP = 10; SP++).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F87351664-192b-44e9-8681-fefec31a9dea%2Fe33cd664-f26a-4904-a9af-f3d421fb2103%2F3z3x71k_processed.png&w=3840&q=75)
Transcribed Image Text:d. This question is about stack implementation. Translate the VM command
"push constant 10" into hack symbolic assembly code. (Hint: the
corresponding hack pseudo-code is: *SP = 10; SP++).
![APPENDIX
1. A-instruction specification
Symbolic syntax:
@value
Binary syntax:
Ovalue
2. C-instruction specification
Symbolic syntax:
Binary syntax:
1
-1
D
A
ID
!A
-D
-A
D+1
A+1
D-1
A-1
D+A
D-A
A-D
D&A
DA
a==0
comp
M
!M
opcode
-M
M+1
M-1
D+M
D-M
M-D
D&M
DIM
a==1
dest= comp; jump
1 1 1 a c1 c2 c3 c4 c5 c6 d1 d2 d3 j1 j2 j3
+4
jump bits
44
not used
c1 c2 c3 c4 c5 c6
1 0
1 0 1 0
1 1
1 1
1 1
1 1 1 0 1 0
1 0 0
0
0 0
RO
R1
0
1
1
0 0
1 1
1 1
1
0
1
1
0 0
0
0
1
1
1 1 1 1
1 1
1 1 0 1 1 1
1
1
1 0
1 0
1 1 0 0
101 1
0 0 0 1 1 1
eeeee 0
0 1 0 1 0 1
R15
15
SCREEN 16384
KBD 24576
comp bits
dest
null
M
D
MD
A
AM
AD
AMD
d1 d2 d3
0 0 0
1
01
e
0 1 1
1
JNE
JLE
JMP
11
1 1
1 1 1
jump j1 j2 j3
null
e
JGT
JEQ
JGE
JLT
001
0 1 0
0 1 1
*
1
11
1 1
1 1 1
dest bits
effect: the value is stored in:
The value is not stored
RAM[A]
D register
RAM[A] and D register
A register
A register and RAM[A]
A register and D register
A register, RAM[A], and D register
3. Built-in symbols of Hack assembly code.
symbol value
0
effect:
jump
no jump
if out
if out = 0 jump
if out 20 jump
if out <0 jump
if out # 0 jump
if out se jump
Unconditional jump
symbol value
SP
0
LCL
ARG
THIS
THAT](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F87351664-192b-44e9-8681-fefec31a9dea%2Fe33cd664-f26a-4904-a9af-f3d421fb2103%2Fm2ytwoo_processed.png&w=3840&q=75)
Transcribed Image Text:APPENDIX
1. A-instruction specification
Symbolic syntax:
@value
Binary syntax:
Ovalue
2. C-instruction specification
Symbolic syntax:
Binary syntax:
1
-1
D
A
ID
!A
-D
-A
D+1
A+1
D-1
A-1
D+A
D-A
A-D
D&A
DA
a==0
comp
M
!M
opcode
-M
M+1
M-1
D+M
D-M
M-D
D&M
DIM
a==1
dest= comp; jump
1 1 1 a c1 c2 c3 c4 c5 c6 d1 d2 d3 j1 j2 j3
+4
jump bits
44
not used
c1 c2 c3 c4 c5 c6
1 0
1 0 1 0
1 1
1 1
1 1
1 1 1 0 1 0
1 0 0
0
0 0
RO
R1
0
1
1
0 0
1 1
1 1
1
0
1
1
0 0
0
0
1
1
1 1 1 1
1 1
1 1 0 1 1 1
1
1
1 0
1 0
1 1 0 0
101 1
0 0 0 1 1 1
eeeee 0
0 1 0 1 0 1
R15
15
SCREEN 16384
KBD 24576
comp bits
dest
null
M
D
MD
A
AM
AD
AMD
d1 d2 d3
0 0 0
1
01
e
0 1 1
1
JNE
JLE
JMP
11
1 1
1 1 1
jump j1 j2 j3
null
e
JGT
JEQ
JGE
JLT
001
0 1 0
0 1 1
*
1
11
1 1
1 1 1
dest bits
effect: the value is stored in:
The value is not stored
RAM[A]
D register
RAM[A] and D register
A register
A register and RAM[A]
A register and D register
A register, RAM[A], and D register
3. Built-in symbols of Hack assembly code.
symbol value
0
effect:
jump
no jump
if out
if out = 0 jump
if out 20 jump
if out <0 jump
if out # 0 jump
if out se jump
Unconditional jump
symbol value
SP
0
LCL
ARG
THIS
THAT
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