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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the slipped part Tutorial Exercise Find the interval of convergence of the power series. (Be sure to include a check for convergence at the endpoints of the interval.) Step 1 (4x)" (an)! Recall the Ratio Test, which states that if a, is a series with nonzero terms, and lim <1, then a converges absolutely. If lim > 1, or lim 1 For any fixed value of x such that x 0, let a (4x)" (an)! and find lim 518 (4x)+1 lim 518 = lim (3(n+1)) 719 (a) (3n) (3n)! (4x)+1) = - (3(n+1))! 880.0 (-00,00) X Step 2 By the Ratio Test, the series converges if lim Submit Skip (you cannot come back) 518 1. Therefore, the series converges for x such that lim =, then, diverges

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the slipped part Tutorial Exercise Find the interval of convergence of the power series. (Be sure to include a check for convergence at the endpoints of the interval.) Step 1 (4x)" (an)! Recall the Ratio Test, which states that if a, is a series with nonzero terms, and lim <1, then a converges absolutely. If lim > 1, or lim 1 For any fixed value of x such that x 0, let a (4x)" (an)! and find lim 518 (4x)+1 lim 518 = lim (3(n+1)) 719 (a) (3n) (3n)! (4x)+1) = - (3(n+1))! 880.0 (-00,00) X Step 2 By the Ratio Test, the series converges if lim Submit Skip (you cannot come back) 518 1. Therefore, the series converges for x such that lim =, then, diverges

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the slipped part Tutorial Exercise Find the interval of convergence of the power series. (Be sure to include a check for convergence at the endpoints of the interval.) Step 1 (4x)" (an)! Recall the Ratio Test, which states that if a, is a series with nonzero terms, and lim <1, then a converges absolutely. If lim > 1, or lim 1 For any fixed value of x such that x 0, let a (4x)" (an)! and find lim 518 (4x)+1 lim 518 = lim (3(n+1)) 719 (a) (3n) (3n)! (4x)+1) = - (3(n+1))! 880.0 (-00,00) X Step 2 By the Ratio Test, the series converges if lim Submit Skip (you cannot come back) 518 1. Therefore, the series converges for x such that lim =, then, diverges
Transcribed Image Text:This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the slipped part Tutorial Exercise Find the interval of convergence of the power series. (Be sure to include a check for convergence at the endpoints of the interval.) Step 1 (4x)" (an)! Recall the Ratio Test, which states that if a, is a series with nonzero terms, and lim <1, then a converges absolutely. If lim > 1, or lim 1 For any fixed value of x such that x 0, let a (4x)" (an)! and find lim 518 (4x)+1 lim 518 = lim (3(n+1)) 719 (a) (3n) (3n)! (4x)+1) = - (3(n+1))! 880.0 (-00,00) X Step 2 By the Ratio Test, the series converges if lim Submit Skip (you cannot come back) 518 1. Therefore, the series converges for x such that lim =, then, diverges
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