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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise A copper rod and an aluminum rod of equal diameter are joined end to end in good thermal contact. The temperature of the free end of the copper rod is held constant at 100°C, and that of the far end of the aluminum rod is held at 0°C. If the copper rod is 0.71 m long, what must be the length of the aluminum rod so that the temperature at the junction is 50°C? Step 1 The rate at which a rod of thermal conductivity k, length L, and cross-sectional area A transfers energy by conduction is given by the following. P = KA - T L Here T is the temperature of the hotter end of the rod and T is the temperature of the cooler end. A T₁ Copper Aluminum T₂ -LCu LAI = When the temperature of the junction between the copper rod and the aluminum rod has stabilized at T, 50°C the copper rod must be transferring energy to the junction at the same rate as the aluminum rod is transferring energy away from the junction. Let T₁ be the temperature of the copper (hotter) end of the rod, T₂ be the temperature of the aluminum (cooler) end of the rod, and T, be the temperature at the junction between the copper and aluminum rods as shown in the diagram. Equating the conduction rates for copper and aluminum, we have код A (71-77) · Τη = KAIA LAI and solving for the length of the aluminum rod gives Τ2 4-(--) LAI = Cu = 42.6 °C -0°C 238 J/s m °C m 397 J/s m °C, °C - 50°C x 10-2 m cm.

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise A copper rod and an aluminum rod of equal diameter are joined end to end in good thermal contact. The temperature of the free end of the copper rod is held constant at 100°C, and that of the far end of the aluminum rod is held at 0°C. If the copper rod is 0.71 m long, what must be the length of the aluminum rod so that the temperature at the junction is 50°C? Step 1 The rate at which a rod of thermal conductivity k, length L, and cross-sectional area A transfers energy by conduction is given by the following. P = KA - T L Here T is the temperature of the hotter end of the rod and T is the temperature of the cooler end. A T₁ Copper Aluminum T₂ -LCu LAI = When the temperature of the junction between the copper rod and the aluminum rod has stabilized at T, 50°C the copper rod must be transferring energy to the junction at the same rate as the aluminum rod is transferring energy away from the junction. Let T₁ be the temperature of the copper (hotter) end of the rod, T₂ be the temperature of the aluminum (cooler) end of the rod, and T, be the temperature at the junction between the copper and aluminum rods as shown in the diagram. Equating the conduction rates for copper and aluminum, we have код A (71-77) · Τη = KAIA LAI and solving for the length of the aluminum rod gives Τ2 4-(--) LAI = Cu = 42.6 °C -0°C 238 J/s m °C m 397 J/s m °C, °C - 50°C x 10-2 m cm.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise A copper rod and an aluminum rod of equal diameter are joined end to end in good thermal contact. The temperature of the free end of the copper rod is held constant at 100°C, and that of the far end of the aluminum rod is held at 0°C. If the copper rod is 0.71 m long, what must be the length of the aluminum rod so that the temperature at the junction is 50°C? Step 1 The rate at which a rod of thermal conductivity k, length L, and cross-sectional area A transfers energy by conduction is given by the following. P = KA - T L Here T is the temperature of the hotter end of the rod and T is the temperature of the cooler end. A T₁ Copper Aluminum T₂ -LCu LAI = When the temperature of the junction between the copper rod and the aluminum rod has stabilized at T, 50°C the copper rod must be transferring energy to the junction at the same rate as the aluminum rod is transferring energy away from the junction. Let T₁ be the temperature of the copper (hotter) end of the rod, T₂ be the temperature of the aluminum (cooler) end of the rod, and T, be the temperature at the junction between the copper and aluminum rods as shown in the diagram. Equating the conduction rates for copper and aluminum, we have код A (71-77) · Τη = KAIA LAI and solving for the length of the aluminum rod gives Τ2 4-(--) LAI = Cu = 42.6 °C -0°C 238 J/s m °C m 397 J/s m °C, °C - 50°C x 10-2 m cm.
Transcribed Image Text:This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise A copper rod and an aluminum rod of equal diameter are joined end to end in good thermal contact. The temperature of the free end of the copper rod is held constant at 100°C, and that of the far end of the aluminum rod is held at 0°C. If the copper rod is 0.71 m long, what must be the length of the aluminum rod so that the temperature at the junction is 50°C? Step 1 The rate at which a rod of thermal conductivity k, length L, and cross-sectional area A transfers energy by conduction is given by the following. P = KA - T L Here T is the temperature of the hotter end of the rod and T is the temperature of the cooler end. A T₁ Copper Aluminum T₂ -LCu LAI = When the temperature of the junction between the copper rod and the aluminum rod has stabilized at T, 50°C the copper rod must be transferring energy to the junction at the same rate as the aluminum rod is transferring energy away from the junction. Let T₁ be the temperature of the copper (hotter) end of the rod, T₂ be the temperature of the aluminum (cooler) end of the rod, and T, be the temperature at the junction between the copper and aluminum rods as shown in the diagram. Equating the conduction rates for copper and aluminum, we have код A (71-77) · Τη = KAIA LAI and solving for the length of the aluminum rod gives Τ2 4-(--) LAI = Cu = 42.6 °C -0°C 238 J/s m °C m 397 J/s m °C, °C - 50°C x 10-2 m cm.
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