This question has multiple parts. Work all the parts to get the most points. a You have a concentration cell with Cu electrodes and [Cu2*- 1.00 M (right side) and 0.0066 M (left side). Calculate the potential for this cell at 25°C. Ecell- b You have a concentration cell with Cu electrodes and [Cu²*-1.00 M (right side) and 0.0066 M (left side). The Cu* ion reacts with NHz to form Cu(NH3)42 by the following equation: Cu2"(aq) + 4NH3(aq) +→ Cu(NH3)4²*(aq) K-1.0x1013 Calculate the new cell potential after enough NH3 is added to the left cell compartment such that at equilibrium [NH3] -1.7 M. Ecell-

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This question has multiple parts. Work all the parts to get the most points.
a You have a concentration cell with Cu electrodes and [Cu²*]-1.00 M (right side) and 0.0066 M (left side). Calculate the potential for this cell at 25°C.
Ecell -
b You have a concentration cell with Cu electrodes and [Cu²*1-1.00 M (right side) and 0.0066 M (left side). The Cu²* jon reacts with NHz to form
Cu(NH3)4²* by the following equation:
Cu2*(aq) + 4NH3(aq) +→ Cu(NH3)4²*(aq)
K-1.0×1013
Calculate the new cell potential after enough NH3 is added to the left cell compartment such that at equilibrium [NH3] - 1.7 M.
Ecell-
Transcribed Image Text:This question has multiple parts. Work all the parts to get the most points. a You have a concentration cell with Cu electrodes and [Cu²*]-1.00 M (right side) and 0.0066 M (left side). Calculate the potential for this cell at 25°C. Ecell - b You have a concentration cell with Cu electrodes and [Cu²*1-1.00 M (right side) and 0.0066 M (left side). The Cu²* jon reacts with NHz to form Cu(NH3)4²* by the following equation: Cu2*(aq) + 4NH3(aq) +→ Cu(NH3)4²*(aq) K-1.0×1013 Calculate the new cell potential after enough NH3 is added to the left cell compartment such that at equilibrium [NH3] - 1.7 M. Ecell-
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