this question from Measurements and Instrumentation course. You should solve the following problem from Measurement Systems by John P. Bentley. all you need in the pic (1+2).

Find the output voltage of the clipper circuit below. Assume diode cut-in voltages of Vγ

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Please show all work, thank you :)

Don't use ai to answer I will report you answer

Ans.a) 79580/Hb)1mH/m Problem: 2.6.12. A galvanometer has a coil resistance of 50 ohms and a current sensitivity of 0.001 micro-ampere per mm. How much is the voltage across its terminals when the deflection is 15 cm at full scale? Ans. 7.5µ V Problem: 2.6.13. A 40-F capacitor is charged to store 0.2 J of energy. An uncharged 60-µF capacitor is then connected in parallel with the first one through perfectly conducting leads. What is the final energy of the system? Ans. 0.12J Problem: 2.6.14. A 40-uF capacitor is connected in parallel with a 60-µF capacitor and across a time-varying voltage source. At a certain instant, the total current supplied by the source is 10 A. Determine the instantaneous currents through the individual capacitors. Ans. 4A and 6A

Trial example of how to use Kirchhoff analysis to determine the initial current in each section along with its direction and the potential difference across the load

Question 1: In the circuit shown below, the output (Vo = 10V Max.) Unipolar. The frequency of Primary is 60 Hz. The diodes are Silicon with VD = 0.7V. a. Sketch the output without a Capacitor. b. Determine Voc without a Capacitor. c. Sketch Vs (at the Secondary). d. Determine Voc with a Capacitor of 10 uF across RL. e. Determine the RMS Value of Vp (at the Primary). f. PIV (Peak Inverse Voltage). 10:1 Output C. 22 k1 All diodes are IN4001. | 00000

For the last two parts, use the diagram to the right. d. V = -1.14V, R = 62, and the voltage across the diode is equal to 0.68V when it is "on". i V = e. V = -0.16V, R = 52, and the voltage across the diode is equal to 0.64V when it is "on". V= i = Vo ww R≤ KHI (Enter at least 3 significant digits. Each answer must be within 1% to be marked correct.) + ひ -

A diode is a two-terminal, electronic device made using semiconductors that is designed to prevent current from flowing in a particular direction. The symbol is a triangle pointing in the direction that (positive) current is allowed to flow and a wall preventing (positive) current from flowing in the opposite direction: 1: A diode has two modes, "on" and "off". When "on", current flows, and when "off", no current flows. We generally view diodes as either "ideal" or "modeled", as described below. "Ideal" view of a diode + The "ideal" diode is either a short circuit or an open circuit. Specifically, when the voltage across its terminals is negative, no current flows, and when current flows, there is zero voltage across its terminals, as pictured below: Diode "Modeled" view of a diode +51 Diode V Ideal Diode "Off" i=0| + U≤0 + I Therefore, with current i and voltage v defined as shown on the left above, for an "ideal" diode: • Current i cannot be negative. Voltage v cannot be positive. .…