This question deals with Pascal's principle. A 3-ton hydraulic jack (a combination of mechanical and hydraulic levers) may be used to lift the side of a car. Fig. 5-20 shows some helpful images of this device that, at the moment, is supporting a load given by the symbol F2. Hydraulic Lever Handle FBD 2= 422 mm = 400 mm piston 2- FA dz = 30 mm- piston 1 hydraulic fluid di =6.5 mm The force FA is the force that would be applied by hand to use the jack. The image labeled Hydraulic Lever identifies the two pistons and their diameters (d1 and d2 ). The force F1 is the force applied by piston 1 on the hydraulic fluid and the force F2 is the resulting force applied by the fluid on piston 2. A.) To support a 3-ton-load (6000 pounds), determine the force F1. Recall that one pound is approximately equal to 4.448 N. B.) Using a typical car jack, determine the force acting on the smaller piston that would be required to support a 3-ton load on the larger piston. The smaller piston's diameter is 6.5 mm and the larger piston's diameter is 30 mm

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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This question deals with Pascal's principle.
A 3-ton hydraulic jack (a combination of mechanical
and hydraulic levers) may be used to lift the side of a
car. Fig. 5-20 shows some helpful images of this
device that, at the moment, is supporting a load
given by the symbol F2.
Hydraulic Lever
Handle FBD
2 = 422 mm
h = 400 mm
piston 2
FA
dz = 30 mm-
- piston 1
hydraulic -
fluid
d = 6.5 mm
The force FA is the force that would be applied by
hand to use the jack.
The image labeled Hydraulic Lever identifies the two
pistons and their diameters (d1 and d2 ). The force F1
is the force applied by piston 1 on the hydraulic fluid
and the force F2 is the resulting force applied by the
fluid on piston 2.
A.) To support a 3-ton-load (6000 pounds), determine
the force F1. Recall that one pound is approximately
equal to 4.448 N.
B.) Using a typical car jack, determine the force acting
on the smaller piston that would be required to
support a 3-ton load on the larger piston. The smaller
piston's diameter is 6.5 mm and the larger piston's
diameter is 30 mm
Transcribed Image Text:This question deals with Pascal's principle. A 3-ton hydraulic jack (a combination of mechanical and hydraulic levers) may be used to lift the side of a car. Fig. 5-20 shows some helpful images of this device that, at the moment, is supporting a load given by the symbol F2. Hydraulic Lever Handle FBD 2 = 422 mm h = 400 mm piston 2 FA dz = 30 mm- - piston 1 hydraulic - fluid d = 6.5 mm The force FA is the force that would be applied by hand to use the jack. The image labeled Hydraulic Lever identifies the two pistons and their diameters (d1 and d2 ). The force F1 is the force applied by piston 1 on the hydraulic fluid and the force F2 is the resulting force applied by the fluid on piston 2. A.) To support a 3-ton-load (6000 pounds), determine the force F1. Recall that one pound is approximately equal to 4.448 N. B.) Using a typical car jack, determine the force acting on the smaller piston that would be required to support a 3-ton load on the larger piston. The smaller piston's diameter is 6.5 mm and the larger piston's diameter is 30 mm
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