How to solve this question, As stated in the Q "We can not use vector component to solve for projection" is confusing me here?I have attached two images, one is the Question itself and second is my attempt on the Question. Please if you could share your working and reasoning behind it, also if you could show an geometric approach. vetor form ofa linem: atab-diretion veutorparalel to thelineposition vedora point onhe lineThis isProjeckion ofã on line Lx-1-K.purallel tothe line"Y=1-XRealize projectionof a is pavallel toBa well.Approcuh :1) Gind a restor ů parallel to line2) ae projection fomula-We khow that reetor is pavallel to lineprojz =[1](-2+C).+ 1/52 This problem is related to core exercise 31 (module 5) in the textbook, and reguires you to do some calculations. In this situation the line, l, below does notpass through the origin. Hence, we cannot use vector components to solve for the projection. You can use similar strategies to the ones used in core exercise31 to find the projection.Let e have vector form = tand let a =-2.0Then proj,ä2.0(Enter your answers in decimal format.)

Answered: Image /qna-images/answer/ddbfd676-e37c-4852-9b38-0559e0bd1b42.jpg

This problem is related to core exercise 31 (module 5) in the textbook, and reguires you to do some calculations. In this situation the line, l, below does not pass through the origin. Hence, we cannot use vector components to solve for the projection. You can use similar strategies to the ones used in core exercise 31 to find the projection. Let e have vector form = t and let a = -2.0 Then proj,ä 2.0 (Enter your answers in decimal format.)

This problem is related to core exercise 31 (module 5) in the textbook, and reguires you to do some calculations. In this situation the line, l, below does not pass through the origin. Hence, we cannot use vector components to solve for the projection. You can use similar strategies to the ones used in core exercise 31 to find the projection. Let e have vector form = t and let a = -2.0 Then proj,ä 2.0 (Enter your answers in decimal format.)

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

How to solve this question, As stated in the Q "We can not use vector component to solve for projection" is confusing me here?

I have attached two images, one is the Question itself and second is my attempt on the Question. Please if you could share your working and reasoning behind it, also if you could show an geometric approach.

vetor form of
a line
m: atab-diretion veutor
paralel to the
line
position vedor
a point on
he line
This is
Projeckion of
ã on line L
x-1-K.
purallel to
the line
"Y=1-X
Realize projection
of a is pavallel to
Ba well.
Approcuh :
1) Gind a restor ů parallel to line
2) ae projection fomula-
We khow that reetor is pavallel to line
projz =
[1]
(-2+C).
+ 1/52

This problem is related to core exercise 31 (module 5) in the textbook, and reguires you to do some calculations. In this situation the line, l, below does not
pass through the origin. Hence, we cannot use vector components to solve for the projection. You can use similar strategies to the ones used in core exercise
31 to find the projection.
Let e have vector form = t
and let a =
-2.0
Then proj,ä
2.0
(Enter your answers in decimal format.)

Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.

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