This problem deals with scaling properties of DTFTs, which are rather different from those of CTFTs. You are welcome to use tables. Let x[n] ⇒ X(en), as described in the sketch below for N € [-π, +π] (PS: Only one period of the signal is shown). -pi/2 1 (Part a) Let y[n] be defined as follows. v[n] = { ™ X(ein) h[n] = { x[n/2] n even n odd +pi/2 Derive an expression for Y(en) in terms of X(e) and sketch it for € [−π, +π] (Part b) Let z[n] be defined as follows. z[n] = (-1)"x[n]. Derive an expression for Z(en) in terms of X(en) and sketch it for N € [−π, +π]. Hint: (-1) = ein (Part c) Let h[n] be defined as follows. x[n] Ω n even n odd Express h[n] interms of x[n] and z[n]. Using this expression, derive an expression for H(en) in terms of X(en) and sketch it for NE [−π, +π].

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5. This problem deals with scaling properties of DTFTs, which are rather different from
those of CTFTs. You are welcome to use tables.
Let x[n]X(ein), as described in the sketch below for N € [−π, +π] (PS: Only one
period of the signal is shown).
-pi/2
1
(Part a) Let y[n] be defined as follows.
y[n] = { 01
x[n/2]
h[n] = {
X(ejn)
x[n]
0
+pi/2
Derive an expression for Y(en) in terms of X(e) and sketch it for N € [-T, +1]
(Part b) Let z[n] be defined as follows.
z[n] = (-1)" x[n].
Derive an expression for Z(en) in terms of X(en) and sketch it for N € [−π, +π].
Hint: (-1)"
einn.
(Part c) Let h[n] be defined as follows.
n even
n odd
+2
n even
n odd
Express h[n] interms of x[n] and z[n]. Using this expression, derive an expression for
H(e) in terms of X(en) and sketch it for N € [-π, +π].
(Part d) Let g[n] be defined as follows.
g[n] = h[2n]
Derive an expression for G(en) in terms of H(en) and sketch it for N € [−π, +π].
Finally, observe that h[2n] = x[2n] and hence, g[n] = x[2n].
Transcribed Image Text:5. This problem deals with scaling properties of DTFTs, which are rather different from those of CTFTs. You are welcome to use tables. Let x[n]X(ein), as described in the sketch below for N € [−π, +π] (PS: Only one period of the signal is shown). -pi/2 1 (Part a) Let y[n] be defined as follows. y[n] = { 01 x[n/2] h[n] = { X(ejn) x[n] 0 +pi/2 Derive an expression for Y(en) in terms of X(e) and sketch it for N € [-T, +1] (Part b) Let z[n] be defined as follows. z[n] = (-1)" x[n]. Derive an expression for Z(en) in terms of X(en) and sketch it for N € [−π, +π]. Hint: (-1)" einn. (Part c) Let h[n] be defined as follows. n even n odd +2 n even n odd Express h[n] interms of x[n] and z[n]. Using this expression, derive an expression for H(e) in terms of X(en) and sketch it for N € [-π, +π]. (Part d) Let g[n] be defined as follows. g[n] = h[2n] Derive an expression for G(en) in terms of H(en) and sketch it for N € [−π, +π]. Finally, observe that h[2n] = x[2n] and hence, g[n] = x[2n].
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