This lab used 6 M HCl that was diluted from a higher concentration.  If your lab instructor asked you to make a solution of HCl with a concentration of 2.0 M from 50.0 mL of a 10.0 M stock solution of HCl, to what total volume would you have to dilute the portion of stock solution?  Units as mL

Q: 550. mL of 2.30 M NaOH from 8.20 M NaOH

A: N1V1=N2V2

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Q: A 77.0 mL77.0 mL portion of a 1.70 M1.70 M solution is diluted to a total volume of 258 mL.258 mL. A…

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Q: 565 mL of water was added to 40.0 mL of 0.550 M MgCI, solution. Assume the volumes are additive.…

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Q: In this station, you will find 400.0 mL of a 0.500 M aqueous solution of calcium chloride. What mass…

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Q: Concentrated sulfuric acid is 18.0 M. You need to make a 2.0 L of 1.0 M solution from this…

A: Given data: M1 = 18 M H2SO4 V1=? M2 = 1.0 M H2SO4 V2 = 2.0 L

Q: In the laboratory, a student dilutes 16.8 mL of a 6.40 M hydrochloric acid solution to a total…

A: • Before dilution,Concentration of HCl solution (M1) = 6.40 MVolume of HCl solution (V1) = 16.8 mL•…

Q: A chemist places 2.6428 g of NaCl in a 100 mL volumetric flask and adds water to the mark and calls…

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Q: In the laboratory, a student dilutes 16.7 mL of a 7.76 M hydrobromic acid solution to a total volume…

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Q: A 25.0 ml solution of 0.500 M NaOH is titrated until neutralized into a 35.0 ml sample of HCl. What…

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Q: How many mL of water is in 950.0 mL of a 0.25 M NaCl solution? The Density of NaCl=2.165g/mL

A: Molarity (M) The equation to calculate molarity is ; M=given massmolar mass×volume of solution(L)

Q: In the laboratory, a student dilutes 22.9 mL of a 11.9 M nitric acid solution to a total volume of…

A: Moles of solute remain constant during dilution. Moles of solute = molarity x volume of solution…

Q: What is the mass of a solution if 25.0 ml of NaOH was added to 35 0 ml of water? Assume a density of…

A: Since the volume of water is not clear, assuming it is 350 mL and the density of solution is 1.00…

Q: A chemist needs 11.32 mL of 1.82 M HCl. What volume in mL of 3.74 M HCl must be diluted in water to…

A: To make 1.83M, 11.32mL HCl from 3.74M HCl, we have to take out some specific volume of 3.74M HCl and…

Q: In the laboratory, a student dilutes 27.2 mL of a 8.33 M hydroiodic acid solution to a volume of…

A: hydroiodic acid solution ( HI ) Initial volume = V1 = 27.2 mL Initial Concentration = M1 = 8.33 M…

Q: In the laboratory, a student dilutes 17.9 mL of a 8.42 M hydrochloric acid solution to a total…

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Q: In the laboratory, a student adds 44.1 mL of water to 12.1 mL of a 0.577 M nitric acid solution.…

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Q: If you had to prepare a 0.200 M HCl solution from 17.0 mL of a 2.60 M HCl stock solution, to what…

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Q: Suppose 1.44 g of potassium sulfate is dissolved in 150. ml. of a 54.0 m M aqueous solution of…

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Q: 525 mL of water was added to 40.0 mL of 0.550 M MgCl₂ solution. Assume the volumes are additive.…

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Q: A solution was made by dissolving 10.00 g of potassium sulfate in 250.0 mL of water. What is the…

A: Note: assuming volume of solution is equal to volume of waterGiven:Mass of K2SO4 = 10.0 gVolume of…

Q: A 10.00 g sample of NaOH is to be used to mal M. What is the total volume of this solution in

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Q: In the laboratory, a student dilutes 17.8 mL of a 8.25 M hydroiodic acid solution to a total volume…

A: Given: Concentration of concentrated HI solution = 8.25 M Volume of concentrated HI solution = 17.8…

Q: A chemist has a 0.800 M solution of potassium hydroxide (molar mass = 56.1 g/mol). What mass of KOH…

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Q: A student is asked to prepare 250 mL of a 0.0104 M NaCl solution. The student found a stock bottle…

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Q: A lab prepared a solution of sulfuric acid with a volume of 5.0x10-4 m3. The solution is further…

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Q: mL of the 50.0 ppt solution in the previous problem are require

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Q: An aqueous solution of sodium nitrate, NaNO3, is made by dissolving 9.38 grams of sodium nitrate in…

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Q: A 64.0 mL64.0 mL portion of a 1.40 M1.40 M solution is diluted to a total volume of 258 mL.258 mL. A…

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Q: Calculate the new molarity if the following dilution is made. Assume the volumes are additive. a.…

A: We can use the formula: M1V1 = M2V2 where M1 is the initial molarity, V1 is the initial volume, M2…

Q: A. 1.00 gram calcium hydroxide in 3.00 liters solution B. 17.0 g potassium dihhydrogen phospate in…

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Q: 227 mL of a 3.2 M solution of KBr is diluted to 731 mL.  What is the new concentration of the…

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Q: when doing a test to find the molarity of solution of hydrochloric acid, the following results were…

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