This is the answer writeClear hand writtenDifference in elevationA₁ + A₂22A (2.545 - 1.625) + (1.405 - 0.725)72A=0.8mi) RL q Qdis below PRLD Q =2RL da- 99.305 m(ii) error in levellingInstrumentat P1.625 +0.8= 2.425 m0.12RL. d P - 0.8100.105 -0.8Readup at P= 1.625erroki(ii) aufularTrue reading at Q=Reading at 2 = 2.545-2.545 - 2.425 =collimation errostam o =e0.1210000 0.00688

Answer is below written clearly.

This is the answer write Clear hand written Difference pence in elevation A₁ + A₂ 2 2 A (2.545 - 1.625) + (1.405 - 0.725) - 2 A= 0.8m i) RL d Q ай belowo Р RLD Q = RL-Q P - 0.8 2 RL da 100.105-0.8 - 99.305 m (ii) error in levelling Instrument Readup at P= 1.625 at P 1.625 +0.8= 2.425 m 0.12 True reading at Q= Reading at 2 = 2.545 errok - 2.545 - २.425 = i(i) aufular collimation errof априве tam o = e 0.12 L 1000 0 0.00688

This is the answer write Clear hand written Difference pence in elevation A₁ + A₂ 2 2 A (2.545 - 1.625) + (1.405 - 0.725) - 2 A= 0.8m i) RL d Q ай belowo Р RLD Q = RL-Q P - 0.8 2 RL da 100.105-0.8 - 99.305 m (ii) error in levelling Instrument Readup at P= 1.625 at P 1.625 +0.8= 2.425 m 0.12 True reading at Q= Reading at 2 = 2.545 errok - 2.545 - २.425 = i(i) aufular collimation errof априве tam o = e 0.12 L 1000 0 0.00688

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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