This is the answer writeClear hand writtenDifference in elevationA₁ + A₂22A (2.545 - 1.625) + (1.405 - 0.725)72A=0.8mi) RL q Qdis below PRLD Q =2RL da- 99.305 m(ii) error in levellingInstrumentat P1.625 +0.8= 2.425 m0.12RL. d P - 0.8100.105 -0.8Readup at P= 1.625erroki(ii) aufularTrue reading at Q=Reading at 2 = 2.545-2.545 - 2.425 =collimation errostam o =e0.1210000 0.00688

Answer is below written clearly.

This is the answer write Clear hand written Difference pence in elevation A₁ + A₂ 2 2 A (2.545 - 1.625) + (1.405 - 0.725) - 2 A= 0.8m i) RL d Q ай belowo Р RLD Q = RL-Q P - 0.8 2 RL da 100.105-0.8 - 99.305 m (ii) error in levelling Instrument Readup at P= 1.625 at P 1.625 +0.8= 2.425 m 0.12 True reading at Q= Reading at 2 = 2.545 errok - 2.545 - २.425 = i(i) aufular collimation errof априве tam o = e 0.12 L 1000 0 0.00688

This is the answer write Clear hand written Difference pence in elevation A₁ + A₂ 2 2 A (2.545 - 1.625) + (1.405 - 0.725) - 2 A= 0.8m i) RL d Q ай belowo Р RLD Q = RL-Q P - 0.8 2 RL da 100.105-0.8 - 99.305 m (ii) error in levelling Instrument Readup at P= 1.625 at P 1.625 +0.8= 2.425 m 0.12 True reading at Q= Reading at 2 = 2.545 errok - 2.545 - २.425 = i(i) aufular collimation errof априве tam o = e 0.12 L 1000 0 0.00688

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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PLEASE ANSWER AS SOON AS POSSIBLE
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Problem 2. Calculate the area of the closed traverse or field in square meters (using coordinate method). 4 -2 12 -10 -8 6 4 ---2 -2 A (4,10) p (2,2) 2 4 6 8 1 B (9,7) C (11,2) 10 12 14
The table below is the page of a level field book. Calculate the reduced levels of points C, F and H if the height of instrument (H.I) for the first and second position of the level= 33.1 and 33.5 respectively. Note: the readings inside the brackets (.....) represent inverted .staff reading St. No. A B с le D E F G H I BS (3.4) ? IS (2.7) 0.9 (1.56) (1.9) 2.6 (0.8) FS 0.7 (2.9) C-35.8, F-32.4, H=36.4 C-36.8, F=32.4, H=36.4 C-34.6, F=30.9, H=36.4 C=36.5, F=34.6, H=36.4 C-32.2, F-35.4, H=34.3
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The table below is the page of a level field book. Calculate the reduced levels of points C, F and H if the height of instrument (H.I) for the first and second position of the level= 33.1 and 33.5 respectively. Note: the readings inside the brackets (.....) represent inverted .staff reading St. No. A B с le D E F G H I BS (3.4) ? IS (2.7) 0.9 (1.56) (1.9) 2.6 (0.8) FS 0.7 (2.9) C-35.8, F-32.4, H=36.4 C-36.8, F=32.4, H=36.4 C-34.6, F=30.9, H=36.4 C=36.5, F=34.6, H=36.4 C-32.2, F-35.4, H=34.3
a) Determine the elevation at each stations. b) Difference in elevation between the 1+20 and 2+00 c) Construct the profile of the ground.
QUESTION 4 Table Q4 shows the booking of levelling fieldwork conducted during light rain. It was later found out that some of the readings are illegible due to the rain water. Complete the booking and perform all checks. Table Q4 BS IS FS HPC RL Remarks 19.245 17.155 TBM 1 RL 17.155 2.010 A 17.169 3.431 0.461 18.784 с (СР) 3.079 D 1.471 20.744 E ? 21.455 ТВМ 2 RL 21.459