This is my proposed mechanism for the synthesis of propylene oxide and methylamine. Is this correct? I'm not sure if I did the latter steps correctly with abstracting the hydrogens and such.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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This is my proposed mechanism for the synthesis of propylene oxide and methylamine. Is this correct? I'm not sure if I did the latter steps correctly with abstracting the hydrogens and such.

**Propylene Oxide and Methylamine Reaction**

This image depicts a chemical reaction between propylene oxide and methylamine (CH₃NH₂), illustrating the nucleophilic attack of methylamine on propylene oxide.

1. **Initial Reaction:**
   - **Reactants:** Propylene oxide and methylamine (CH₃NH₂).
   - An arrow from the nitrogen in methylamine indicates the nucleophilic attack on the epoxide ring of propylene oxide.

2. **Intermediate Formation:**
   - The result is a charged intermediate with a positive charge on the nitrogen showing an intermediate amine-alcohol structure.
   - The epoxide ring opens with the formation of a negative charge on the oxygen atom.

3. **Further Transformation:**
   - A rearrangement occurs leading to the formation of a hydroxyl group (OH).
   - The negative charge on the oxygen shifts as the intermediate rearranges.
  
4. **Final Product:**
   - The reaction completes with the formation of an aminopropanol compound, specifically with a structure of CH₃NH on one side and an OH group on the opposite.

**Diagrams/Arrows:**
- Curved arrows indicate electron movement in the reaction mechanism, depicting the step-by-step transformation of reactants to products.
- The circled structure at the bottom right is the final product: a molecule with CH₃-NH and an OH group attached to the carbon chain.

This schematic illustrates a typical example of nucleophilic substitution in organic chemistry, specifically involving epoxides and amines.
Transcribed Image Text:**Propylene Oxide and Methylamine Reaction** This image depicts a chemical reaction between propylene oxide and methylamine (CH₃NH₂), illustrating the nucleophilic attack of methylamine on propylene oxide. 1. **Initial Reaction:** - **Reactants:** Propylene oxide and methylamine (CH₃NH₂). - An arrow from the nitrogen in methylamine indicates the nucleophilic attack on the epoxide ring of propylene oxide. 2. **Intermediate Formation:** - The result is a charged intermediate with a positive charge on the nitrogen showing an intermediate amine-alcohol structure. - The epoxide ring opens with the formation of a negative charge on the oxygen atom. 3. **Further Transformation:** - A rearrangement occurs leading to the formation of a hydroxyl group (OH). - The negative charge on the oxygen shifts as the intermediate rearranges. 4. **Final Product:** - The reaction completes with the formation of an aminopropanol compound, specifically with a structure of CH₃NH on one side and an OH group on the opposite. **Diagrams/Arrows:** - Curved arrows indicate electron movement in the reaction mechanism, depicting the step-by-step transformation of reactants to products. - The circled structure at the bottom right is the final product: a molecule with CH₃-NH and an OH group attached to the carbon chain. This schematic illustrates a typical example of nucleophilic substitution in organic chemistry, specifically involving epoxides and amines.
Expert Solution
Step 1

In your mechanism, the first step and the final product are correct. 

But the extraction of H+ from CH3NH2 and protonation step of CH3NH- are not correct. 

The correct extraction of H+ and explanation is shown below:

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