This is more of a double-check question: The question in the book says "Factor the expression completely. Begin by factoring out the lowest power of each common factor." x-3/2+2x-1/2+x1/2 I facotred out x-3/2, and got: x-3/2(1+2x+x2). I originally had this as my final answer, but the answer guide says "x-3/2(1+x2). Is this because it says to factor completely? So that the (x2+2x+1) becomes (x+1)(x+1)?
This is more of a double-check question: The question in the book says "Factor the expression completely. Begin by factoring out the lowest power of each common factor." x-3/2+2x-1/2+x1/2 I facotred out x-3/2, and got: x-3/2(1+2x+x2). I originally had this as my final answer, but the answer guide says "x-3/2(1+x2). Is this because it says to factor completely? So that the (x2+2x+1) becomes (x+1)(x+1)?
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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This is more of a double-check question:
The question in the book says "Factor the expression completely. Begin by factoring out the lowest power of each common factor."
x-3/2+2x-1/2+x1/2
I facotred out x-3/2, and got:
x-3/2(1+2x+x2). I originally had this as my final answer, but the answer guide says "x-3/2(1+x2). Is this because it says to factor completely? So that the (x2+2x+1) becomes (x+1)(x+1)?
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