This is Design Problem 5.D1 in Materials Science and Engineering: An Introductio 9th Edition. An answer is given in the back of the textbook, but the answer is not explained. It is desired to enrich the partial pressure of hydrogen in a hydrogen-nitrogen ga mixture for which the partial pressures of both gases are 0.1013 MPa (1 atm). It has been proposed to accomplish this by passing both gases through a thin shee of some metal at an elevated temperature; inasmuch as hydrogen diffuses through the plate at a higher rate than does nitrogen, the partial pressure of hydrogen will be higher on the exit side of the sheet. The design calls for partial pressures of 0.051 MPa (0.5 atm) and 0.01013 MPa (0.1 atm), respectively, for hydrogen and nitrogen. mol 2.5 * 10° * VPH,exp(- -27800J/mol. m3 CH RT Concentration of Hydrogen mol Concentration of Nitrogen = CN -37600J/mol 2.75 * 103 VPN, * exp( * RT m2 1.4 * ,-13400J/mol, * exp(- 10-7 Diffusion Coefficient of Hydrogen = DH S %3D RT %3D m² 3.0 * 10- * exp( –76150J/mol RT Diffusion Coefficient of Nitrogen = DN Book Question: Is it possible to purify hydrogen gas in this manner? Book Answer: Not possible My Question: Why? Could you walk me through it step by step as to why it is not possible?
This is Design Problem 5.D1 in Materials Science and Engineering: An Introductio 9th Edition. An answer is given in the back of the textbook, but the answer is not explained. It is desired to enrich the partial pressure of hydrogen in a hydrogen-nitrogen ga mixture for which the partial pressures of both gases are 0.1013 MPa (1 atm). It has been proposed to accomplish this by passing both gases through a thin shee of some metal at an elevated temperature; inasmuch as hydrogen diffuses through the plate at a higher rate than does nitrogen, the partial pressure of hydrogen will be higher on the exit side of the sheet. The design calls for partial pressures of 0.051 MPa (0.5 atm) and 0.01013 MPa (0.1 atm), respectively, for hydrogen and nitrogen. mol 2.5 * 10° * VPH,exp(- -27800J/mol. m3 CH RT Concentration of Hydrogen mol Concentration of Nitrogen = CN -37600J/mol 2.75 * 103 VPN, * exp( * RT m2 1.4 * ,-13400J/mol, * exp(- 10-7 Diffusion Coefficient of Hydrogen = DH S %3D RT %3D m² 3.0 * 10- * exp( –76150J/mol RT Diffusion Coefficient of Nitrogen = DN Book Question: Is it possible to purify hydrogen gas in this manner? Book Answer: Not possible My Question: Why? Could you walk me through it step by step as to why it is not possible?
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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