This gives us TA 1 8 cos(0) + 16 cos( os() +16 cos COS(1) +16 cos 4 COS(1/6) + 8 cos(1) 5(1)] = 8 = (rounded to six decimal places) Therefore, using the Trapezoidal Rule with n = 4 and rounding to six decimal places we have 1 √² 8 cos(x²) dx =
This gives us TA 1 8 cos(0) + 16 cos( os() +16 cos COS(1) +16 cos 4 COS(1/6) + 8 cos(1) 5(1)] = 8 = (rounded to six decimal places) Therefore, using the Trapezoidal Rule with n = 4 and rounding to six decimal places we have 1 √² 8 cos(x²) dx =
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![This gives us
TA
1
8 cos(0) + 16 cos(
os()
+16 cos
COS(1)
+16 cos
4
COS(1/6)
+ 8 cos(1)
5(1)]
=
8
=
(rounded to six decimal places)
Therefore, using the Trapezoidal Rule with n = 4 and rounding to six decimal places we have
1
√² 8 cos(x²) dx =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbba7f514-2c91-4585-b277-764d3d0d203a%2Fde0f6076-355b-442c-a1ea-14251c9cf145%2Fybp0y9i_processed.png&w=3840&q=75)
Transcribed Image Text:This gives us
TA
1
8 cos(0) + 16 cos(
os()
+16 cos
COS(1)
+16 cos
4
COS(1/6)
+ 8 cos(1)
5(1)]
=
8
=
(rounded to six decimal places)
Therefore, using the Trapezoidal Rule with n = 4 and rounding to six decimal places we have
1
√² 8 cos(x²) dx =
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