This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the extreme values of the function subject to the gi constraint. f(x, y, z) = xy²z, x² + y² + z² = 64 maximum value 16/32 -16/32 minimum value

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Q: Use Lagrange multipliers to determine the maximum and minimum values ​​of the function.

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A: The given integral is: I=∫x2+x+8(x-1)x2+9dx

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