Hi, I created this computer JAVA program that is supposed to give you 3 attempts to insert a password and when you have exceeded that amout, the program ends and when you inser the right password, it's supposed to say access granted.For some reason, when I insert my password, it says that i should try again. Can someone look at my code and see whats the problem? Thank you The image shows an online compiler interface with an error message. Here is a detailed transcription and explanation:### Code Snippet:```javapublic class CellPhone { String password = "Batman";}```### Error Message:The compiler outputs the following error:```Main.java:33: error: variable purchaser is already defined in method main(String[]) String purchaser; ^1 error```### Explanation:- **Code Section**: The code snippet defines a simple Java class named `CellPhone` with a single `String` variable called `password`, initialized to "Batman".- **Error**: The error message indicates an issue in a file named `Main.java` on line 33. It states that the variable `purchaser` is already defined within the `main` method, leading to a compilation failure.### Interface Overview:- **Editor Section**: On the left, code can be written and edited.- **Compile and Run Options**: At the top are options to run, debug, stop, share, save, and beautify the code.- **Output/Error Pane**: Below the editor is a pane displaying errors and output.### Graphs/Diagrams:There are no graphs or diagrams in the image.### Summary:This image illustrates a common error encountered during Java programming—defining a variable more than once within the same scope, which causes compilation issues. The image displays a Java programming environment in the OnlineGDB compiler. The main code segment includes a class named `Main` with a `main` method. The method aims to validate a password with limited attempts.Here's a detailed description of the code:```javaimport java.util.Scanner;public class Main { public static void main(String[] args) { CellPhone purchaser = new CellPhone(); int multiAttempts = 0; boolean isPassValid = false; Scanner keyboard = new Scanner(System.in); System.out.print("Enter password here: "); String entPass = keyboard.nextLine(); String password = ""; do { if (entPass.equals(purchaser.password)) { System.out.println("Access Granted"); isPassValid = true; } if (!isPassValid) { System.out.println("Error! Try again"); password = keyboard.nextLine(); multiAttempts++; } } while (multiAttempts < 3 && !isPassValid); if (multiAttempts == 3) { System.out.println("# of attempts exceeded, PROGRAM TERMINATED!!"); System.exit(0); } }}```### Key Points:- **Scanner Usage:** Captures user input for password validation.- **Conditional Logic:** Verifies the entered password against the stored password, indicating either "Access Granted" or prompting to retry upon failure.- **Loop and Attempts:** Allows a maximum of three attempts using a `do-while` loop.- **Exit Condition:** Terminates the program if the maximum attempts are exceeded.### Error Description:In the lower console panel, a compilation error is highlighted:```Main.java:13: error: variable purchaser is already defined in method main(String[]) String purchaser; ^1 error```This error indicates that there is a redeclaration of the `purchaser` variable in the `main` method, which is causing a conflict with the existing `CellPhone purchaser`.This error must be resolved for successful compilation by removing or renaming the redundant `purchaser` variable.### Graphs or Diagrams:There are no graphs or diagrams in the image.

I have given java code without an error below.Java Code: Main.Java : import java.util.Scanner;public class Main { public static void main(String[] args) { // TODO Auto-generated method stub CellPhone purchaser = new CellPhone(); int mulAttemps = 1; boolean isPassValid = false; Scanner keyboard = new Scanner(System.in); System.out.println("Enter password here: "); String password = keyboard.nextLine(); do { if (password.equals(purchaser.password)) { System.out.println("Access Granted"); isPassValid = true; } if (!isPassValid) { System.out.println("Error! Try again"); password = keyboard.nextLine(); mulAttemps++; } }while (mulAttemps < 3 && !isPassValid); if (mulAttemps == 3) { System.out.println("# of attemps exceeded, PROGRAM TERMINATED!!"); System.exit(0); } }} CellPhone.Java : public class CellPhone { String password = "Batman";} Output:

Answered: this computer JAVA program that is…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Hi, I created this computer JAVA program that is supposed to give you 3 attempts to insert a password and when you have exceeded that amout, the program ends and when you inser the right password, it's supposed to say access granted.

For some reason, when I insert my password, it says that i should try again. Can someone look at my code and see whats the problem? Thank you