This code segment calculates the elements of the numeric array H(5,5). Each element of H when i=j is determined by the formula (hij =i+j - 1). The elements of the other positions in the array are equal 1.
This code segment calculates the elements of the numeric array H(5,5). Each element of H when i=j is determined by the formula (hij =i+j - 1). The elements of the other positions in the array are equal 1.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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This code segment calculates the
elements of the numeric array H(5,5).
Each element of H when i=j is
determined by the formula (hij = i + j
- 1). The elements of the other
positions in the array are equal 1.
For I=1 To 5
For J = 1 To 5
1-........
2-....
3-......
4-..
5-.
6-....
1-If I = J Then 2-H(I, J) = (1 + J - 1) 3-Else 4-
H(I, J) = 1 5-Next J, I 6-End If
1-If I = J Then 2-H(I, J) = (1 + J - 1) 3-Else 4-
H(I, J) = 1 5-End If 6-Next J, I
1-If I = J Then 2-H(I, J) = 1 3-Else 4-H(I, J) = (1
+ J-1) 5-End If 6-Next J, I
1-If I > J Then 2-H(I, J) = (I + J - 1) 3-Else 4-
H(I, J) = 1 5-End If 6-Next J, I
1-If I < J Then 2-H(I, J) = (I + J - 1) 3-Else 4-
H(I, J) = 1 5-End If 6-Next J, I
1-If I = J Then 2-H(I, J) = (1 + J - 1) 3-Elseif 4-
H(I, J) = 1 5-End If 6-Next J, I](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10982431-4498-4a7c-9c62-b66957cf753f%2F2229988a-ba2b-4224-a415-adabee36ecfc%2F2q3k288_processed.jpeg&w=3840&q=75)
Transcribed Image Text:!
This code segment calculates the
elements of the numeric array H(5,5).
Each element of H when i=j is
determined by the formula (hij = i + j
- 1). The elements of the other
positions in the array are equal 1.
For I=1 To 5
For J = 1 To 5
1-........
2-....
3-......
4-..
5-.
6-....
1-If I = J Then 2-H(I, J) = (1 + J - 1) 3-Else 4-
H(I, J) = 1 5-Next J, I 6-End If
1-If I = J Then 2-H(I, J) = (1 + J - 1) 3-Else 4-
H(I, J) = 1 5-End If 6-Next J, I
1-If I = J Then 2-H(I, J) = 1 3-Else 4-H(I, J) = (1
+ J-1) 5-End If 6-Next J, I
1-If I > J Then 2-H(I, J) = (I + J - 1) 3-Else 4-
H(I, J) = 1 5-End If 6-Next J, I
1-If I < J Then 2-H(I, J) = (I + J - 1) 3-Else 4-
H(I, J) = 1 5-End If 6-Next J, I
1-If I = J Then 2-H(I, J) = (1 + J - 1) 3-Elseif 4-
H(I, J) = 1 5-End If 6-Next J, I
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