They found that data was significant at level 0.05. This means that: A trucking company pays its drivers by the mile. Some of its employees request that they drive through the night and early morning so that they may avoid traffic and complete more miles in a shorter amount of time. The company conducts a test of significance with a sample of 100 drivers to determine if, on average, letting their drives drive through the night does result in more miles being completed. Employees of this company usually average 12,000 miles every month. The company tests the hypotheses H_0 : \mu = 12,000H0​:μ=12,000 and H_a : \mu > 12,000Ha​:μ>12,000 with a random sample of 50 drivers who opt to drive through the night.   They found that data was significant at level 0.05. This means that: a. The company rejects the null hypothesis. So they can conclude that allowing their employees to drive through the night will not result in more miles and trips being completed in a month.   b. The company rejects the null hypothesis. So they can conclude that allowing their employees to drive through the night will result in more miles and trips being completed in a month.   c. The company fails to reject the null hypothesis. So they can conclude that the average miles per month of every employee is exactly 12,000 miles, regardless of if they drive through the night.   d.The company fails to reject the null hypothesis, and cannot conclude that there is any effect on the average miles per month of its employee if they drive through the night.

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A trucking company pays its drivers by the mile. Some of its employees request that they drive through the night and early morning so that they may avoid traffic and complete more miles in a shorter amount of time. The company conducts a test of significance with a sample of 100 drivers to determine if, on average, letting their drives drive through the night does result in more miles being completed. Employees of this company usually average 12,000 miles every month. The company tests the hypotheses H_0 : \mu = 12,000H0​:μ=12,000 and H_a : \mu > 12,000Ha​:μ>12,000 with a random sample of 50 drivers who opt to drive through the night.

 

They found that data was significant at level 0.05. This means that:

A trucking company pays its drivers by the mile. Some of its employees request that they drive through the night and early morning so that they may avoid traffic and complete more miles in a shorter amount of time. The company conducts a test of significance with a sample of 100 drivers to determine if, on average, letting their drives drive through the night does result in more miles being completed. Employees of this company usually average 12,000 miles every month. The company tests the hypotheses H_0 : \mu = 12,000H0​:μ=12,000 and H_a : \mu > 12,000Ha​:μ>12,000 with a random sample of 50 drivers who opt to drive through the night.

 

They found that data was significant at level 0.05. This means that:

a. The company rejects the null hypothesis. So they can conclude that allowing their employees to drive through the night will not result in more miles and trips being completed in a month.
 
b. The company rejects the null hypothesis. So they can conclude that allowing their employees to drive through the night will result in more miles and trips being completed in a month.
 
c. The company fails to reject the null hypothesis. So they can conclude that the average miles per month of every employee is exactly 12,000 miles, regardless of if they drive through the night.
 
d.The company fails to reject the null hypothesis, and cannot conclude that there is any effect on the average miles per month of its employee if they drive through the night.
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